在我的开发环境中,我得到了这个错误。我花了很长时间试图弄清楚这件事,尤其是因为我想象它正盯着我的脸。我针对我的一个模型创建了一个新的ModelForm,然后开始得到这个错误。如果我注释掉我的admin.site.register(ModelName)文件中的“models.py (ModelName)”行,它就会消失,但是我不能再检查管理站点中的数据了.
,这里是错误:
Environment:
Request Method: GET
Request URL: http://127.0.0.1:8000/admin/
Django Version: 1.3.1
Python Version: 2.7.2
Installed Applications:
['django.contrib.auth',
'django.contrib.contenttypes',
'django.contrib.sessions',
'django.contrib.sites',
'django.contrib.messages',
'django.contrib.staticfiles',
'django.contrib.admin',
'django.contrib.admindocs',
'azcerts.certmanager']
Installed Middleware:
('django.middleware.common.CommonMiddleware',
'django.contrib.sessions.middleware.SessionMiddleware',
'django.middleware.csrf.CsrfViewMiddleware',
'django.middleware.csrf.CsrfResponseMiddleware',
'django.contrib.auth.middleware.AuthenticationMiddleware',
'django.contrib.messages.middleware.MessageMiddleware')
Traceback:
File "C:\Python27\lib\site-packages\django\core\handlers\base.py" in get_response
101. request.path_info)
File "C:\Python27\lib\site-packages\django\core\urlresolvers.py" in resolve
250. for pattern in self.url_patterns:
File "C:\Python27\lib\site-packages\django\core\urlresolvers.py" in _get_url_patterns
279. patterns = getattr(self.urlconf_module, "urlpatterns", self.urlconf_module)
File "C:\Python27\lib\site-packages\django\core\urlresolvers.py" in _get_urlconf_module
274. self._urlconf_module = import_module(self.urlconf_name)
File "C:\Python27\lib\site-packages\django\utils\importlib.py" in import_module
35. __import__(name)
File "C:\Users\ntagg\Code\azcerts\urls.py" in <module>
3. from certmanager.views import addone
File "C:\Users\ntagg\Code\azcerts\certmanager\views.py" in <module>
4. from forms import CertForm
File "C:\Users\ntagg\Code\azcerts\forms.py" in <module>
4. from certmanager.models import UserProfile, Cert
File "C:\Users\ntagg\Code\azcerts\certmanager\models.py" in <module>
52. admin.site.register(UserProfile)
File "C:\Python27\lib\site-packages\django\contrib\admin\sites.py" in register
85. raise AlreadyRegistered('The model %s is already registered' % model.__name__)
Exception Type: AlreadyRegistered at /admin/
Exception Value: The model UserProfile is already registered
这里是models.py:
#models.py
from django.db import models
from django.contrib import admin
from django.contrib.auth.models import User
from django.contrib.localflavor.us.models import USStateField
class Cert(models.Model):
# My fields are here...
def __unicode__(self):
return self.fieldname
class UserProfile(models.Model):
# My fields are here...
def __unicode__(self):
return self.fieldname
admin.site.register(UserProfile)
admin.site.register(Cert)
发布于 2012-03-01 20:29:57
不要在你的models.py
中注册你的模型,为你的应用程序创建一个admin.py
,然后在那里做。
# admin.py
from django.contrib import admin
from myapp.models import Cert, UserProfile
admin.site.register(Cert)
admin.site.register(UserProfile)
解释:
创建模型表单时,Django两次导入您的models.py
:一次是使用路径azcerts.certmanager.models
(就像在INSTALLED_APPS
中那样),另一次是使用路径certmanager.models
(在定义模型表单的模块中)。Django第二次导入models.py时,它再次尝试注册模型,并给出了错误。
通过将寄存器命令移动到admin.py中,可以确保模型只注册一次。
在像这样的两种不同的路径上导入models.py
有点麻烦。Django 1.4中的默认项目布局已经更改,这将防止出现这样的问题。
https://stackoverflow.com/questions/9523268
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