创建if语句时如何创建范围
创建if语句时如何创建范围
提问于 2020-07-30 21:35:50
我对蟒蛇很陌生。我需要帮助处理这段代码：
price = 1000000
credit = int(input("What is your credit score? "))
if credit >= 670:
print("Since you have a high credit score, you will have to only put down 10% for your new home! ")
new_price = price/10
print(f"The price you will have to pay is ${new_price}!")
elif credit <= 670:
print("Due to your low credit score, you will have to put down 20% for your new home.")
new_price = price/5
print(f"The price you will have to pay is ${new_price}!")
elif credit <= 0:
print("Sorry, that is not a valid credit score!")
elif credit >= 850:
print("Sorry, that is not a valid credit score!")
else:
print("Sorry, but you haven't typed in a number! Run the program to try again.")
print("Have a great day!")所以，我试着用一个非常高的数字运行代码，认为它会导致“对不起，这不是一个有效的信用评分”，但后来我意识到，我在这里没有限制：
if credit >= 670:
print("Since you have a high credit score, you will have to only put down 10% for your new home! ")
new_price = price/10
print(f"The price you will have to pay is ${new_price}!")因此，它认为任何670分或更高的分数都是高信用分数。是否有代码，或某种方法，我可以使高信用评分至少是670，最高850？
回答 1
Stack Overflow用户
发布于 2020-07-30 21:41:21
您有与670等号的不同条件，如果不是elif状态，您应该与您独占，因为它们实际上是相互排斥的，如下所示：
if credit < 670:
elif 670 <= credit <= 850:
else:
然后，如果希望检查所有条件语句，请使用几个if语句。如果您使用if, elif和else，那么一旦一个大小写匹配，就不会检查其他情况。当只使用if时，将检查所有语句，无论前面是否匹配。
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原文链接：
https://stackoverflow.com/questions/63181712
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