问如何从字符串中的计算器表达式中删除前导零？python

EN

def cut_zeroes(Z):
    i, res = 0, []
    n = len(Z)

    while i < n:
        j = i
        while i < n and Z[i] not in '+-/*':
            i += 1
        res.append(int(Z[j:i]))

        if i < n:
            res.append(Z[i])

        i += 1

    return ''.join(map(str,res))
  

Z = "00123+0567*29/03-700"
print(cut_zeroes(Z))

Z = "00123+0567*29/03-7"
print Z

import re
res = re.split(r'(\D)', Z)
print res

empty_lst = []
for i in res :
    i = i.lstrip("0")
    empty_lst.append(i)
    print i
print empty_lst
new_str = ''.join(empty_lst)
print new_str

def zero_simplify(Z):
    from re import sub
    return [char for char in sub("0{2,}", "0", Z)]

Z = "00123+0567*29/03-7+0-000"
Z = zero_simplify(Z)
pos = len(Z)-1
while pos>-1:
    if Z[pos]=="0":
        end = pos
        while Z[pos] == "0":
            pos-=1
            if pos==-1:
                del Z[pos+1:end+1]
        if (not Z[pos].isdigit()) and (Z[pos] != ".") and (Z[pos] == "0"):
            del Z[pos+1:end+1]
    else:
        pos-=1
Z = "".join(Z)
print(Z)

def zero_simplify(Z):
    from re import sub
    return [char for char in sub("0{2,}", "0", Z)]

def remove_unnecessary_zeroes(Z):
    Z = [char for char in Z]
    pos = len(Z)-1
    while pos>-1:
        if Z[pos]=="0":
            end = pos
            while Z[pos] == "0":
                pos-=1
                if pos==-1:
                    del Z[pos+1:end+1]
            if (not Z[pos].isdigit()) and (Z[pos] != ".") and (Z[pos] == "0"):
                del Z[pos+1:end+1]
        else:
            pos-=1
    Z = "".join(Z)
    return Z
Z = "00123+0567*29/03-7+0-000"
print(remove_unnecessary_zeroes(Z))