问当status_code = 200时，使用python请求重试

EN

import requests
import time

MAX_RETRY = 5


def make_request():
    '''This makes a single request to the server to get data from it.'''
    # Replace 'get' with whichever method you're using, and the URL with the actual API URL
    r = requests.get('http://api.example.com')
    
    # If r.status_code is not 200, treat it as an error.
    if r.status_code != 200:
        raise RuntimeError(f"HTTP Response Code {r.status_code} received from server."
    else:
        j = r.json()
        if j['error'] != 0:
            raise RuntimeError(f"API Error Code {j['error']} received from server."
        else:
            return j
            

def request_with_retry(backoff_in_seconds=1):
    '''This makes a request retry up to MAX_RETRY set above with exponential backoff.'''
    attempts = 1
    while True:
        try:
            data = make_request()
            return data
        except RuntimeError as err:
            print(err)
            if attempts > MAX_RETRY:
                raise RuntimeError("Maximum number of attempts exceeded, aborting.")
                
            sleep = backoff_in_seconds * 2 ** (attempts - 1)
            print(f"Retrying request (attempt #{attempts}) in {sleep} seconds...")
            time.sleep(sleep)
            attempts += 1

# This code actually *calls* these functions which contain the request with retry and 
# exponential backoff *and* the individual request process for a single request.
try:
    data = request_with_retry()
except RuntimeError as err:
    print(err)
    exit(1)