我正尝试在我的Kotlin项目中添加另一个专门用于集成测试的模块--与kotlin插件创建的标准test模块并存。下面是我添加sourceset的当前配置
sourceSets {
testIntegration {
java.srcDir 'src/testIntegration/java'
kotlin.srcDir 'src/testIntegration/kotlin'
resources.srcDir 'src/testIntegration/resources'
compileClasspath += main.output
runtimeClasspath += main.output
}
}
configurations {
provided
testCompile.extendsFrom provided
testIntegrationCompile.extendsFrom testCompile
testIntegrationRuntime.extendsFrom testRuntime
}
task testIntegration(type: Test) {
testClassesDirs = sourceSets.testIntegration.output.classesDirs
classpath = sourceSets.testIntegration.runtimeClasspath
}这似乎是可行的,但是IntelliJ不会将新的源码集作为测试模块。我可以手动标记它,但每次Gradle运行时它都会重置。这也意味着Intellij在项目结构设置中填写的是Output Path而不是Test Output Path字段。
要修复以下配置,请执行以下操作:
apply plugin: 'idea'
idea {
module {
testSourceDirs += project.sourceSets.testIntegration.java.srcDirs
testSourceDirs += project.sourceSets.testIntegration.kotlin.srcDirs
testSourceDirs += project.sourceSets.testIntegration.resources.srcDirs
}
}然而,这似乎告诉IntelliJ,测试是\out\test\classes,这与标准的‘Test Output Path’模块相同,并导致冲突问题。我希望它将输出路径保留为原来的\out\testIntegration\classes,否则就会使用它。
有没有办法指示IntelliJ正确地选择这个新的测试源集并填写正确的输出路径?
发布于 2021-05-28 19:00:02
如果你想在kotlin gradle构建脚本中用你的自定义测试sourceSets配置idea gradle插件,你可以这样做:
val testIntegrationSrcDirName = "testIntegration"
sourceSets {
...
create(testIntegrationSrcDirName) {
compileClasspath += sourceSets.main.get().output + sourceSets.test.get().output // take also unit test source and resources
runtimeClasspath += sourceSets.main.get().output + sourceSets.test.get().output // take also unit test source and resources
}
}
...
idea {
module {
testSourceDirs = testSourceDirs + sourceSets[testIntegrationSrcDirName].allSource.srcDirs
}
}
val testIntegrationImplementation: Configuration by configurations.getting {
extendsFrom(configurations.implementation.get())
}
configurations["${testIntegrationSrcDirName}RuntimeOnly"].extendsFrom(configurations.runtimeOnly.get())
... https://stackoverflow.com/questions/51455726
复制相似问题