通过删除括号中的括号和逗号,尝试将列表1转换为列表2,如下面的代码所示,这样我就可以将字符串用于SQLite select查询:
[('Mark Zuckerberg',), ('Bill Gates',), ('Tim Cook',), ('Wlliam Sidis',), ('Elon Musk',)]
['Mark Zuckerberg', 'Bill Gates', 'Tim Cook', 'William Sidis', 'Elon Musk']发布于 2018-03-01 17:58:44
在列表中读取行和存储时使用str( row )
list=[('Mark Zuckerberg',), ('Bill Gates',), ('Tim Cook',), ('Wlliam Sidis',), ('Elon Musk',)]
listoutput=[i[0] for i in list]
print(listoutput)检查输出如下
<iframe height="400px" width="100%" src="https://repl.it/repls/PortlyCarefulCodegeneration?lite=true" scrolling="no" frameborder="no" allowtransparency="true" allowfullscreen="true" sandbox="allow-forms allow-pointer-lock allow-popups allow-same-origin allow-scripts allow-modals"></iframe>
发布于 2018-10-04 21:40:29
试试这个-
region=['INDIA','ME',"SEA","AFRICA","SAARC","LATIN AMERICA"]
print region
lst= str(region)
lst.strip("[").strip("]").strip("'")发布于 2018-03-01 18:07:17
假设你有一个这样的列表,
animal_raw = [('cat', ), ('dog', ), ('elephant', )]现在我们将把它转换成您要求的没有逗号和括号的代码。
animal = [i[0] for i in animal_raw]现在,print(animal)。您现在应该可以获得输出,
['cat', 'dog', 'elephant']https://stackoverflow.com/questions/49046930
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