blocks|key|1857834|text|使用perl作为编码器；它被保证是无buggy的，无处不在，而且有了管道，它仍然相当干净：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1857835|ls+%7C+perl+-e+'use+JSON;+@in=grep(s/\n$//,+<>);+print+encode_json(\@in)."\n";'|code-block|syntax|javascript|1857836|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Use perl as the encoder; it's guaranteed to be non-buggy, is everywhere, and with pipes, it's still reasonably clean:

<pre><code>ls | perl -e 'use JSON; @in=grep(s/\n$//, &lt;&gt;); print encode_json(\@in)."\n";'
</code></pre>

blocks|key|2176572|text|是的，但是转角的情况和Unicode的处理会把你逼上绝路。最好委托一种本机支持它的脚本语言。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2176573|$+ls
あ++a++"a"++à++a+b++私
$+python+-c+'import+os,+json;+print+json.dumps(os.listdir("."))'
["\u00e0",+"\"a\"",+"\u79c1",+"a+b",+"\u3042",+"a"]|code-block|syntax|javascript|2176574|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Yes, but the corner cases and Unicode handling will drive you up the wall. Better to delegate to a scripting language that supports it natively.

<pre><code>$ ls
あ a "a" à a b 私
$ python -c 'import os, json; print json.dumps(os.listdir("."))'
["\u00e0", "\"a\"", "\u79c1", "a b", "\u3042", "a"]
</code></pre>

blocks|key|2181896|text|如果您知道没有文件名包含换行符，请使用jq：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2181897|ls+%7C+jq+-R+-s+-c+'split("\n")[:-1]'|offset|length|style|CODE|2181898|对jq的标志的简短解释：|2181899|2181900|-R将输入视为字符串而不是JSON|unordered-list-item|2181901|-s将所有行连接到一个array|2181902|-c中创建紧凑的output|2181903|[:-1]删除输出数组中的最后一个空字符串|2181904|2181905|这需要1.4或更高版本的jq。如果对你不起作用，试试这个：|2181906|ls+%7C+jq+-R+'[.]'+%7C+jq+-s+-c+'add'|2181907|entityMap^0|0|0|Z|0|0|0|0|2|0|0|2|0|0|2|0|0|5|0|0|0|0|X|0^^$0|@$1|2|3|4|5|6|7|10|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|11|8|@$D|12|E|13|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|14|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|15|8|@]|9|@]|A|$]]|$1|K|3|L|5|M|7|16|8|@$D|17|E|18|F|G]]|9|@]|A|$]]|$1|N|3|O|5|M|7|19|8|@$D|1A|E|1B|F|G]]|9|@]|A|$]]|$1|P|3|Q|5|M|7|1C|8|@$D|1D|E|1E|F|G]]|9|@]|A|$]]|$1|R|3|S|5|M|7|1F|8|@$D|1G|E|1H|F|G]]|9|@]|A|$]]|$1|T|3|-4|5|6|7|1I|8|@]|9|@]|A|$]]|$1|U|3|V|5|6|7|1J|8|@]|9|@]|A|$]]|$1|W|3|X|5|6|7|1K|8|@$D|1L|E|1M|F|G]]|9|@]|A|$]]|$1|Y|3|-4|5|6|7|1N|8|@]|9|@]|A|$]]]|Z|$]]

If you know that no filename contains newlines, use jq:

<code>ls | jq -R -s -c 'split("\n")[:-1]'</code>

Short explanation of the flags to jq:

<ul>
<li><code>-R</code> treats the input as string instead of JSON</li>
<li><code>-s</code> joins all lines into an array</li>
<li><code>-c</code> creates a compact output</li>
<li><code>[:-1]</code> removes the last empty string in the output array</li>
</ul>

This requires version 1.4 or later of jq. Try this if it doesn't work for you:

<code>ls | jq -R '[.]' | jq -s -c 'add'</code>

blocks|key|1857795|text|您好，您可以使用sed和awk做到这一点：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1857796|ls+%7C+awk+'+BEGIN+{+ORS+=+"";+print+"[";+}+{+print+"\/\@"$0"\/\@";+}+END+{+print+"]";+}'+%7C+sed+"s%5E\"%5E\\\\\"%5Eg;s%5E\/\@\/\@%5E\",+\"%5Eg;s%5E\/\@%5E\"%5Eg"|code-block|syntax|javascript|1857797|编辑:已更新以解决"和空格的问题。我使用/@作为"的替换模式，因为/不是文件名的有效字符。|offset|length|style|CODE|1857798|entityMap^0|0|0|9|1|K|2|O|1|X|1|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]|$I|T|J|U|K|L]|$I|V|J|W|K|L]|$I|X|J|Y|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|N|$]]

Hello you can do that with sed and awk:

<pre><code>ls | awk ' BEGIN { ORS = ""; print "["; } { print "\/\@"$0"\/\@"; } END { print "]"; }' | sed "s^\"^\\\\\"^g;s^\/\@\/\@^\", \"^g;s^\/\@^\"^g"
</code></pre>

EDIT: updated to solve the problem with <code>"</code> and spaces. I use <code>/@</code> as replacement pattern for <code>"</code>, since <code>/</code> is not a valid character for filename.

blocks|key|1161079|text|这是一条狂欢的路线|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1161080|echo+'['+;+ls+--format=commas%7Csed+-e+'s/%5E/\"/'%7Csed+-e+'s/,$/\",/'%7Csed+-e+'s/$[%5E,]$$/\1\"\]/'%7Csed+-e+'s/,+/\",+\"/g'|code-block|syntax|javascript|1161081|无法正确处理文件名中的"、\或某些逗号。此外，如果ls在文件名之间添加换行符，也会这样做。|offset|length|style|CODE|1161082|entityMap^0|0|0|B|1|D|1|P|2|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]|$I|T|J|U|K|L]|$I|V|J|W|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|X|8|@]|9|@]|A|$]]]|N|$]]

Here's a bash line

<pre><code>echo '[' ; ls --format=commas|sed -e 's/^/\"/'|sed -e 's/,$/\",/'|sed -e 's/$[^,]$$/\1\"\]/'|sed -e 's/, /\", \"/g'
</code></pre>

Won't properly deal with <code>"</code>, <code>\</code> or some commas in the name of the file. Also, if <code>ls</code> puts newlines between filenames, so will this.

blocks|key|1161140|text|我还在寻找一种将Linux文件夹/文件树输出到某个JSON或XML文件的方法。为什么不使用这个简单的终端命令：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1161141|$+tree+--dirsfirst+--noreport+-n+-X+-i+-s+-D+-f+-o+my.xml|code-block|syntax|javascript|1161142|因此，只需使用linux+tree命令，并配置您自己的参数。这里-X给出了XML输出！对我来说，这是可以的，我猜有一些脚本可以将XML转换为JSON。|offset|length|style|CODE|1161143|注意:我认为this涵盖了同样的问题。|1161144|entityMap|0|LINK|mutability|MUTABLE|url|https://unix.stackexchange.com/questions/90115/convert-output-of-tree-command-to-json-format/^0|0|0|W|2|0|6|4|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Y|8|@$I|Z|J|10|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|11|8|@]|9|@$I|12|J|13|1|14]]|A|$]]|$1|O|3|-4|5|6|7|15|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V]]]]

I was also searching for a way to output a Linux folder / file tree to some JSON or XML file. Why not use this simple terminal command:

<pre><code>$ tree --dirsfirst --noreport -n -X -i -s -D -f -o my.xml
</code></pre>

so, just the linux tree command, and config your own parameters. Here <code>-X</code> gives XML output! For me, that's OK, and i guess there's some script to convert XML to JSON .. 

NOTE: I think <a href="https://unix.stackexchange.com/questions/90115/convert-output-of-tree-command-to-json-format/">this</a> covers the same question.

blocks|key|215367|text|大多数Linux机器都已经安装了python。你要做的就是：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|215368|python+-c+'import+os,+json;+print+json.dumps(os.listdir("/yourdirectory"))'|code-block|syntax|javascript|215369|这是为了。目录中，您可以添加任何路径。|215370|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Most of the Linux machine already has python. all you have to do is:

<pre><code>python -c 'import os, json; print json.dumps(os.listdir("/yourdirectory"))'
</code></pre>

This is for . directory , you can add any path.

blocks|key|1161025|text|就个人而言，我会编写运行ls命令的脚本，将输出发送到您选择的文件，同时解析输出以将其格式化为有效的JSON格式。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1161026|我确信一个简单的Bash文件就可以完成这项工作。|1161027|Bash+ouput|offset|length|1161028|entityMap|0|LINK|mutability|MUTABLE|url|http://www.skorks.com/2009/09/output-redirection-with-bash/^0|0|0|0|A|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|Q|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|R|8|@]|9|@$F|S|G|T|1|U]]|A|$]]|$1|H|3|-4|5|6|7|V|8|@]|9|@]|A|$]]]|I|$J|$5|K|L|M|A|$N|O]]]]

Personnaly, I would code script that would run the command ls, send the output to a file of you choice while parsing the output to make format it to a valid JSON format.

I'm sure that a simple Bash file will do the work.

<a href="http://www.skorks.com/2009/09/output-redirection-with-bash/" rel="nofollow">Bash ouput</a>

blocks|key|1857700|text|你不能使用这样的python脚本吗？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1857701|myOutput+=+subprocess.check_output["ls"]
output+=+["%2Bstr(e)%2B"+for+e+in+myOutput]
return+output|code-block|syntax|javascript|1857702|我没有检查它是否正常工作，但您可以找到规范here|offset|length|1857703|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.python.org/library/subprocess.html#module-subprocess^0|0|0|L|4|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

Can't you use a python script like this?

<pre><code>myOutput = subprocess.check_output["ls"]
output = ["+str(e)+" for e in myOutput]
return output
</code></pre>

I didn't check if it works, but you can find the specification <a href="http://docs.python.org/library/subprocess.html#module-subprocess" rel="nofollow">here</a>

blocks|key|215179|text|应该很简单。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|215180|$+cat+ls2json.bash
#!/bin/bash
echo+-n+'['
for+FILE+in+$(ls+%7C+sed+-e+'s/"/\\"/g')
do
echo+-n+\"${FILE}\",
done
echo+-en+\\b']'|code-block|syntax|javascript|215181|然后运行：|215182|$+./ls2json.bash+>+json.out|215183|但是python会更简单。|215184|import+os
directory+=+'/some/dir'
ls+=+os.listdir(directory)
dirstring+=+str(ls)
print+dirstring.replace("'",'"')|215185|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

Should be pretty easy.

<pre><code>$ cat ls2json.bash
#!/bin/bash
echo -n '['
for FILE in $(ls | sed -e 's/"/\\"/g')
do
echo -n \"${FILE}\",
done
echo -en \\b']'
</code></pre>

then run:

<pre><code>$ ./ls2json.bash &gt; json.out
</code></pre>

but python would be even easier

<pre><code>import os
directory = '/some/dir'
ls = os.listdir(directory)
dirstring = str(ls)
print dirstring.replace("'",'"')
</code></pre>

blocks|key|2176627|text|不要使用bash，使用脚本语言。未经测试的perl示例：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2176628|use+JSON;
my+@ls_output+=+`ls`;+##+probably+better+to+use+a+perl+module+to+do+this,+like+DirHandle
print+encode_json(+@ls_output+);|code-block|syntax|javascript|2176629|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Don't use bash, use a scripting language. Untested perl example: 

<pre><code>use JSON;
my @ls_output = `ls`; ## probably better to use a perl module to do this, like DirHandle
print encode_json( @ls_output );
</code></pre>

Is it possible to use a bash script to format the output of the <code>ls</code> to a json array? To be valid json, all names of the dirs and files need to be wrapped in double quotes, seperated by a comma, and the entire thing needs to be wrapped in square brackets. I.e. convert:

<pre><code>jeroen@jeroen-ubuntu:~/Desktop$ ls
foo.txt bar baz
</code></pre>

to

<pre><code>[ "foo.txt", "bar", "baz" ]
</code></pre>

edit: I strongly prefer something that works across all my Linux servers; hence rather not depend on python, but have a pure bash solution.

convert bash `ls` output to json array

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技术创作特训营有奖征文

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没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

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可以使用bash脚本将ls的输出格式化为json数组吗？要使json有效，目录和文件的所有名称都需要用双引号括起来，用逗号分隔，整个内容需要用方括号括起来。例如，转换：jeroen@jeroen-ubuntu:~/Desktop$ lsfoo.txt bar baz至[ "foo.txt", "bar", "baz" ]编辑:我强烈喜欢在我所有的Linux服务器上都能工作的东西；因此，我不想依赖p

问将bash `ls`输出转换为json数组
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