blocks|key|2613057|text|使用黑魔法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2613058|$array+=+preg_split('~\\\\.(*SKIP)(*FAIL)%7C\%7C~s',+$string);|code-block|syntax|javascript|2613059|\\\\.匹配后跟字符的反斜杠，(*SKIP)(*FAIL)跳过它，\%7C匹配您的分隔符。|offset|length|style|CODE|2613060|entityMap^0|0|0|0|5|G|E|Y|2|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]|$I|T|J|U|K|L]|$I|V|J|W|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|X|8|@]|9|@]|A|$]]]|N|$]]

Use dark magic:

<pre><code>$array = preg_split('~\\\\.(*SKIP)(*FAIL)|\|~s', $string);
</code></pre>

<code>\\\\.</code> matches a backslash followed by a character, <code>(*SKIP)(*FAIL)</code> skips it and <code>\|</code> matches your delimiter.

blocks|key|996112|text|与split(...)相比，使用某种“扫描”函数更直观，它的操作方式类似于词法记号赋予器。在PHP中，这就是preg_match_all函数。你只需简单地说你想匹配：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|996113|后跟%7C|996114|or或%7C|unordered-list-item|996115|
|996116|repeat+#1或#2的|996117|+\或\以外的事物至少一次|ordered-list-item|996118|996119|996120|以下demo：|996121|$input+=+"1%7C2\\%7C2%7C3\\\\%7C4\\\\\\%7C4";
echo+$input+.+"\n\n";
preg_match_all('/(?:\\\\.%7C[%5E\\\\%7C])%2B/',+$input,+$parts);
print_r($parts[0]);|code-block|syntax|javascript|996122|将打印：|996123|1%7C2\%7C2%7C3\\%7C4\\\%7C4

Array
(
++++[0]+=>+1
++++[1]+=>+2\%7C2
++++[2]+=>+3\\
++++[3]+=>+4\\\%7C4
)|996124|entityMap^0|1|A|1I|E|0|2|1|0|3|1|0|0|0|1|1|3|1|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|16|8|@$9|17|A|18|B|C]|$9|19|A|1A|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|1B|8|@$9|1C|A|1D|B|C]]|D|@]|E|$]]|$1|H|3|I|5|J|7|1E|8|@$9|1F|A|1G|B|C]]|D|@]|E|$]]|$1|K|3|L|5|6|7|1H|8|@]|D|@]|E|$]]|$1|M|3|N|5|J|7|1I|8|@]|D|@]|E|$]]|$1|O|3|P|5|Q|7|1J|8|@$9|1K|A|1L|B|C]|$9|1M|A|1N|B|C]]|D|@]|E|$]]|$1|R|3|-4|5|6|7|1O|8|@]|D|@]|E|$]]|$1|S|3|-4|5|6|7|1P|8|@]|D|@]|E|$]]|$1|T|3|U|5|6|7|1Q|8|@]|D|@]|E|$]]|$1|V|3|W|5|X|7|1R|8|@]|D|@]|E|$Y|Z]]|$1|10|3|11|5|6|7|1S|8|@]|D|@]|E|$]]|$1|12|3|13|5|X|7|1T|8|@]|D|@]|E|$Y|Z]]|$1|14|3|-4|5|6|7|1U|8|@]|D|@]|E|$]]]|15|$]]

Instead of <code>split(...)</code>, it's IMO more intuitive to use some sort of "scan" function that operates like a lexical tokenizer. In PHP that would be the <code>preg_match_all</code> function. You simply say you want to match:

<ol>
<li>something other than a <code>\</code> or <code>|</code></li>
<li>or a <code>\</code> followed by a <code>\</code> or <code>|</code></li>
<li>repeat #1 or #2 at least once</li>
</ol>

The following demo:

<pre class="lang-php prettyprint-override"><code>$input = "1|2\\|2|3\\\\|4\\\\\\|4";
echo $input . "\n\n";
preg_match_all('/(?:\\\\.|[^\\\\|])+/', $input, $parts);
print_r($parts[0]);
</code></pre>

will print:

<pre class="lang-none prettyprint-override"><code>1|2\|2|3\\|4\\\|4

Array
(
 [0] =&gt; 1
 [1] =&gt; 2\|2
 [2] =&gt; 3\\
 [3] =&gt; 4\\\|4
)
</code></pre>

blocks|key|4687137|text|最近，我想出了一个解决方案：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4687138|$array+=+preg_split('~+((?<!\\\\)%7C(?<=[%5E\\\\](\\\\\\\\)%2B))+\%7C+~x',+$string);|code-block|syntax|javascript|4687139|但黑魔法解决方案的速度仍然快了三倍。|4687140|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Recently I devised a solution:

<pre><code>$array = preg_split('~ ((?&lt;!\\\\)|(?&lt;=[^\\\\](\\\\\\\\)+)) \| ~x', $string);
</code></pre>

But the black magic solution is still three times faster.

blocks|key|2613105|text|对于未来的读者，这里有一个通用的解决方案。它是基于尼基克对(*SKIP)(*FAIL)的想法|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2613106|function+split_escaped($delimiter,+$escaper,+$text)
{
++++$d+=+preg_quote($delimiter,+"~");
++++$e+=+preg_quote($escaper,+"~");
++++$tokens+=+preg_split(
++++++++'~'+.+$e+.+'('+.+$e+.+'%7C'+.+$d+.+')(*SKIP)(*FAIL)%7C'+.+$d+.+'~',
++++++++$text
++++);
++++$escaperReplacement+=+str_replace(['\\',+'$'],+['\\\\',+'\\$'],+$escaper);
++++$delimiterReplacement+=+str_replace(['\\',+'$'],+['\\\\',+'\\$'],+$delimiter);
++++return+preg_replace(
++++++++['~'+.+$e+.+$e+.+'~',+'~'+.+$e+.+$d+.+'~'],
++++++++[$escaperReplacement,+$delimiterReplacement],
++++++++$tokens
++++);
}|code-block|syntax|javascript|2613107|试一试：|2613108|//+the+base+situation:
$text+=+"asdf\\,fds\\,ddf,\\\\,f\\,,dd";
$delimiter+=+",";
$escaper+=+"\\";
print_r(split_escaped($delimiter,+$escaper,+$text));

//+other+signs:
$text+=+"dk!%25fj%25slak!%25df!!jlskj%25%25dfl%25isr%25!%25%25jlf";
$delimiter+=+"%25";
$escaper+=+"!";
print_r(split_escaped($delimiter,+$escaper,+$text));

//+delimiter+with+multiple+characters:
$text+=+"aksd()jflaksd())jflkas(('()j()fkl'()()as()d('')jf";
$delimiter+=+"()";
$escaper+=+"'";
print_r(split_escaped($delimiter,+$escaper,+$text));

//+escaper+is+same+as+delimiter:
$text+=+"asfl''asjf'lkas'''jfkl''d'jsl";
$delimiter+=+"'";
$escaper+=+"'";
print_r(split_escaped($delimiter,+$escaper,+$text));|2613109|输出：|2613110|Array
(
++++[0]+=>+asdf,fds,ddf
++++[1]+=>+\
++++[2]+=>+f,
++++[3]+=>+dd
)
Array
(
++++[0]+=>+dk%25fj
++++[1]+=>+slak%25df!jlskj
++++[2]+=>+
++++[3]+=>+dfl
++++[4]+=>+isr
++++[5]+=>+%25
++++[6]+=>+jlf
++++)
Array
(
++++[0]+=>+aksd
++++[1]+=>+jflaksd
++++[2]+=>+)jfl'kas((()j
++++[3]+=>+fkl()
++++[4]+=>+as
++++[5]+=>+d(')jf
)
Array
(
++++[0]+=>+asfl'asjf
++++[1]+=>+lkas'
++++[2]+=>+jfkl'd
++++[3]+=>+jsl
)|2613111|注意：有一个理论层面的问题：implode('::',+['a:',+':b'])和implode('::',+['a',+'',+'b'])结果相同的字符串：'a::::b'。内爆也可能是一个有趣的问题。|BOLD|2613112|entityMap^0|T|E|0|0|0|0|0|0|0|3|E|R|16|T|28|8|0^^$0|@$1|2|3|4|5|6|7|X|8|@$9|Y|A|Z|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|10|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|11|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|12|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|13|8|@]|D|@]|E|$]]|$1|Q|3|R|5|H|7|14|8|@]|D|@]|E|$I|J]]|$1|S|3|T|5|6|7|15|8|@$9|16|A|17|B|U]|$9|18|A|19|B|C]|$9|1A|A|1B|B|C]|$9|1C|A|1D|B|C]]|D|@]|E|$]]|$1|V|3|-4|5|6|7|1E|8|@]|D|@]|E|$]]]|W|$]]

For future readers, here is a universal solution. It is based on NikiC's idea with <code>(*SKIP)(*FAIL)</code>:



<pre class="lang-php prettyprint-override"><code>function split_escaped($delimiter, $escaper, $text)
{
 $d = preg_quote($delimiter, "~");
 $e = preg_quote($escaper, "~");
 $tokens = preg_split(
 '~' . $e . '(' . $e . '|' . $d . ')(*SKIP)(*FAIL)|' . $d . '~',
 $text
 );
 $escaperReplacement = str_replace(['\\', '$'], ['\\\\', '\\$'], $escaper);
 $delimiterReplacement = str_replace(['\\', '$'], ['\\\\', '\\$'], $delimiter);
 return preg_replace(
 ['~' . $e . $e . '~', '~' . $e . $d . '~'],
 [$escaperReplacement, $delimiterReplacement],
 $tokens
 );
}
</code></pre>

Make a try:



<pre class="lang-php prettyprint-override"><code>// the base situation:
$text = "asdf\\,fds\\,ddf,\\\\,f\\,,dd";
$delimiter = ",";
$escaper = "\\";
print_r(split_escaped($delimiter, $escaper, $text));

// other signs:
$text = "dk!%fj%slak!%df!!jlskj%%dfl%isr%!%%jlf";
$delimiter = "%";
$escaper = "!";
print_r(split_escaped($delimiter, $escaper, $text));

// delimiter with multiple characters:
$text = "aksd()jflaksd())jflkas(('()j()fkl'()()as()d('')jf";
$delimiter = "()";
$escaper = "'";
print_r(split_escaped($delimiter, $escaper, $text));

// escaper is same as delimiter:
$text = "asfl''asjf'lkas'''jfkl''d'jsl";
$delimiter = "'";
$escaper = "'";
print_r(split_escaped($delimiter, $escaper, $text));
</code></pre>

Output:



<pre class="lang-none prettyprint-override"><code>Array
(
 [0] =&gt; asdf,fds,ddf
 [1] =&gt; \
 [2] =&gt; f,
 [3] =&gt; dd
)
Array
(
 [0] =&gt; dk%fj
 [1] =&gt; slak%df!jlskj
 [2] =&gt; 
 [3] =&gt; dfl
 [4] =&gt; isr
 [5] =&gt; %
 [6] =&gt; jlf
 )
Array
(
 [0] =&gt; aksd
 [1] =&gt; jflaksd
 [2] =&gt; )jfl'kas((()j
 [3] =&gt; fkl()
 [4] =&gt; as
 [5] =&gt; d(')jf
)
Array
(
 [0] =&gt; asfl'asjf
 [1] =&gt; lkas'
 [2] =&gt; jfkl'd
 [3] =&gt; jsl
)
</code></pre>

Note: There is a theoretical level problem: <code>implode('::', ['a:', ':b'])</code> and <code>implode('::', ['a', '', 'b'])</code> result the same string: <code>'a::::b'</code>. Imploding can be also an interesting problem.

blocks|key|2898115|text|正则表达式的运行速度非常慢。一种更好的方法是在拆分之前从字符串中删除转义字符，然后将它们放回其中：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2898116|$foo+=+'a,b%7C,c,d%7C%7C,e';

function+splitEscaped($str,+$delimiter,$escapeChar+=+'\\')+{
++++//Just+some+temporary+strings+to+use+as+markers+that+will+not+appear+in+the+original+string
++++$double+=+"\0\0\0_doub";
++++$escaped+=+"\0\0\0_esc";
++++$str+=+str_replace($escapeChar+.+$escapeChar,+$double,+$str);
++++$str+=+str_replace($escapeChar+.+$delimiter,+$escaped,+$str);

++++$split+=+explode($delimiter,+$str);
++++foreach+($split+as+&$val)+$val+=+str_replace([$double,+$escaped],+[$escapeChar,+$delimiter],+$val);
++++return+$split;
}

print_r(splitEscaped($foo,+',',+'%7C'));|code-block|syntax|javascript|2898117|它在“，”上拆分，但如果用"%7C“转义就不会。它还支持双重转义，因此在拆分发生后，"%7C%7C“变成了单个"%7C”：|2898118|Array+(+[0]+=>+a+[1]+=>+b,c+[2]+=>+d%7C+[3]+=>+e+)+|2898119|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Regex is painfully slow. A better method is removing escaped characters from the string prior to splitting then putting them back in:

<pre><code>$foo = 'a,b|,c,d||,e';

function splitEscaped($str, $delimiter,$escapeChar = '\\') {
 //Just some temporary strings to use as markers that will not appear in the original string
 $double = "\0\0\0_doub";
 $escaped = "\0\0\0_esc";
 $str = str_replace($escapeChar . $escapeChar, $double, $str);
 $str = str_replace($escapeChar . $delimiter, $escaped, $str);

 $split = explode($delimiter, $str);
 foreach ($split as &amp;$val) $val = str_replace([$double, $escaped], [$escapeChar, $delimiter], $val);
 return $split;
}

print_r(splitEscaped($foo, ',', '|'));
</code></pre>

which splits on ',' but not if escaped with "|". It also supports double escaping so "||" becomes a single "|" after the split happens:

<pre><code>Array ( [0] =&gt; a [1] =&gt; b,c [2] =&gt; d| [3] =&gt; e ) 
</code></pre>

Split string by delimiter, but not if it is escaped

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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如何通过分隔符拆分字符串，但如果字符串被转义则不能？例如，我有一个字符串：1|2\|2|3\\|4\\\|4分隔符是|，转义的分隔符是\|。此外，我想忽略转义的反斜杠，因此在\\|中，|仍然是分隔符。因此，使用上面的字符串，结果应该是：[0] => 1[1] => 2\|2[2] => 3\\[3] => 4\\\|4

问按分隔符拆分字符串，但如果对其进行转义则不会
EN

回答 5

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问按分隔符拆分字符串，但如果对其进行转义则不会EN

回答 5

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问按分隔符拆分字符串，但如果对其进行转义则不会
EN