如何在Python3.5上创建用户输入10个整数的程序
如何在Python3.5上创建用户输入10个整数的程序
提问于 2016-02-07 07:22:33
用户将输入10个整数，作为回报，程序将告诉用户输入的10个整数中哪个是最大的奇数。我已经为下面的工作粘贴了脚本。我的工作的问题是，当最大的数字是偶数时，它返回一个错误，我如何让python忽略最大的偶数，继续到下一个最大的奇数。
n1 = int(input('enter integer 1: '))
n2 = int(input('enter integer 2: '))
n3 = int(input('enter integer 3: '))
n4 = int(input('enter integer 4: '))
n5 = int(input('enter integer 5: '))
n6 = int(input('enter integer 6: '))
n7 = int(input('enter integer 7: '))
n8 = int(input('enter integer 8: '))
n9 = int(input('enter integer 9: '))
n10 = int(input('enter integer 10: '))
if n1%2!=0:
a=n1
if n2%2!=0:
b=n2
if n3%2!=0:
c=n3
if n4%2!=0:
d=n4
if n5%2!=0:
e=n5
if n6%2!=0:
f=n6
if n7%2!=0:
g=n7
if n8%2!=0:
h=n8
if n9%2!=0:
i=n9
if n10%2!=0:
j=n10
if n1>n2 and n1>n3 and n1>n4 and n1>n5 and n1>n6 and n1>n7 and n1>n8 and n1>n9 and n1>n10:
print(n1, 'is the largest odd number')
if n2>n1 and n2>n3 and n2>n4 and n2>n5 and n2>n6 and n2>n7 and n2>n8 and n2>n9 and n2>n10:
print(b, 'is the largest odd number')
if n3>n1 and n3>n2 and n3>n4 and n3>n5 and n3>n6 and n3>n7 and n3>n8 and n3>n9 and n3>n10:
print(c, 'is the largest odd number')
if n4>n1 and n4>n2 and n4>n3 and n4>n5 and n4>n6 and n4>n7 and n4>n8 and n4>n9 and n4>n10:
print(d, 'is the largest odd number')
if n5>n1 and n5>n2 and n5>n3 and n5>n4 and n5>n6 and n5>n7 and n5>n8 and n5>n9 and n5>n10:
print(e, 'is the largest odd number')
if n6>n1 and n6>n2 and n6>n3 and n6>n4 and n6>n5 and n6>n7 and n6>n8 and n6>n9 and n6>n10:
print(f, 'is the largest odd number')
if n7>n1 and n7>n2 and n7>n3 and n7>n4 and n7>n5 and n7>n6 and n7>n8 and n7>n9 and n7>n10:
print(g, 'is the largest odd number')
if n8>n1 and n8>n2 and n8>n3 and n8>n4 and n8>n5 and n8>n6 and n8>n7 and n8>n9 and n8>n10:
print(h, 'is the largest odd number')
if n9>n1 and n9>n2 and n9>n3 and n9>n4 and n9>n5 and n9>n6 and n9>n7 and n9>n8 and n9>n10:
print(i, 'is the largest odd number')
if n10>n1 and n10>n2 and n10>n3 and n10>n4 and n10>n5 and n10>n6 and n10>n7 and n10>n8 and n10>n9:
print(j, 'is the largest odd number')回答 3
Stack Overflow用户
发布于 2016-02-07 07:27:12
我不完全确定你遇到了什么问题，你得到了什么错误，但你真的应该考虑使用循环来代替。如下所示：
odd_numbers = []
for i in range(1, 11):
input = int(input('enter integer {}: '.format(i)))
if input % 2:
odd_numbers.append(input)
if odd_numbers:
print('{} is the largest odd number'.format(max(odd_numbers)))
else:
print('There were no odd numbers entered')通常情况下，我会将这篇文章作为注释来写，但希望帮助OP了解如何使用循环
Stack Overflow用户
发布于 2016-02-07 07:37:58
代码的许多问题中的第一个问题是，当您尝试打印它时，可能没有定义j。
话虽如此，您的代码确实需要重构。查看列表、循环、生成器和max函数。开始尝试修复你的代码是没有意义的。
以下是一个简明版本的建议：
def max_odd():
prompt = 'enter integer {}: '
entered = (int(input(prompt.format(i+1))) for i in range(10))
try:
return max(x for x in entered if x%2)
except ValueError: # no odd number
return None演示：
>>> max_odd()
enter integer 1: 1
enter integer 2: 2
enter integer 3: 3
enter integer 4: 4
enter integer 5: 5
enter integer 6: 6
enter integer 7: 7
enter integer 8: 8
enter integer 9: 9
enter integer 10: 10
9Stack Overflow用户
发布于 2016-02-07 07:40:56
考虑做一些类似的事情：
maximum=0 #Variable to store the maximum. Since this is even, if we get to the end of the program and it's still 0, we can be sure there were no odd numbers entered.
for i in range(1,11): #Loop from i=1 to i=10
n=int(input 'enter integer: {}'.format(i)) #Ask for an integer input
if (n%2) != 0: #If the number is odd
if maximum==0 or n>maximum: #Then if it is bigger than the old maximum or it's the first odd number
maximum=n #Then set it as the new maximum
if (maximum != 0): #If any odd numbers were entered
print(maximum, ' is the largest odd number') #Output the biggest
else: #If none of the numbers were odd
print('all input numbers were even') #Then complain页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/35247737
复制相关文章
相似问题
腾讯云开发者
