首页
学习
活动
专区
圈层
工具
发布
首页
学习
活动
专区
圈层
工具
MCP广场
社区首页 >问答首页 >我在SQL Alchemy中的关系有什么问题?

我在SQL Alchemy中的关系有什么问题?
EN

Stack Overflow用户
提问于 2013-07-20 03:05:01
回答 2查看 14.2K关注 0票数 17

我正在使用SQLAlchemy和Flask为我的应用程序创建关系。我最近重写了关系,而且,无论我做了什么更改,我都会得到错误:

代码语言:javascript
运行
复制
sqlalchemy.exc.NoForeignKeysError: Could not determine join condition between 
parent/child tables on relationship CurriculumVersion.enrollments - there are 
no foreign keys linking these tables.  Ensure that referencing columns are 
associated with a ForeignKey or ForeignKeyConstraint, or specify
a 'primaryjoin' expression.

在我的模型上:

代码语言:javascript
运行
复制
class User(db.Model, AuthUser):
    id = db.Column(db.Integer, primary_key=True)
    tf_login = db.Column(db.String(255), unique=True, nullable=False) # can assume is an email
    password = db.Column(db.String(120), nullable=False)
    salt = db.Column(db.String(80))
    role = db.Column(db.String(80)) # for later when have different permission types
    zoho_contactid = db.Column(db.String(20), unique=True, nullable=False)
    created_asof = db.Column(db.DateTime, default=datetime.datetime.utcnow)
    enrollments = db.relationship('Enrollment', backref='enrollment', lazy='dynamic')
    firstname = db.Column(db.String(80))
    lastname = db.Column(db.String(80))


    def __repr__(self):
        return '#%d tf_login: %s, First Name: %s Last Name: %s created_asof %s' % (self.id, self.tf_login, self.firstname, self.lastname, self.created_asof)

    def __getstate__(self):
        return {
            'id': self.id,
            'tf_login': self.tf_login,
            'firstname': self.firstname,
            'lastname': self.lastname,
            'role': self.role,
            'created_asof': self.created_asof,
        }

    @classmethod
    def load_current_user(cls, apply_timeout=True):
        data = get_current_user_data(apply_timeout)
        if not data:
            return None
        return cls.query.filter(cls.email==data['email']).one()
        return '#%d Course Name: %s, Course Version: %s, Closing Date: %s' %(self.id, self.course_name, self.course_version, self.closing_date)

class Enrollment(db.Model, AuthUser):
    id = db.Column(db.Integer, primary_key=True)
    user_id = db.Column(db.Integer, db.ForeignKey('user.id'))
    version_id = db.Column(db.Integer, db.ForeignKey('curriculumversion.id'))
    cohort_id = db.Column(db.Integer, db.ForeignKey('cohort.id'))

    def __repr__(self):
        return '#%d User ID: %d Version ID: %d, Cohort ID: %d' %(self.id, self.user_id, self.version_id, self.cohort_id)

class Cohort(db.Model, AuthUser):
    id = db.Column(db.Integer, primary_key=True)
    days_to_completion = db.Column(db.String(20))
    course_id = db.Column(db.Integer, db.ForeignKey('course.id'))
    enrollments = db.relationship('Enrollment', backref='enrollment', lazy='dynamic')

    def __repr__(self):
        return '#%d Days To Completion: %s' %(self.id, self.days_to_completion)


class CurriculumVersion(db.Model, AuthUser):
    id = db.Column(db.Integer, primary_key=True)
    version_number = db.Column(db.String(6))
    date_implemented = db.Column(db.DateTime)
    course_id = db.Column(db.Integer, db.ForeignKey('course.id'))
    enrollments = db.relationship('Enrollment', backref='enrollment', lazy='dynamic')

    def __repr__(self):
        return '#%d Version Number: %s, Date Implemented: %s' %(self.id, self.version_number, self.date_implemented)

class Course(db.Model, AuthUser):
    id = db.Column(db.Integer, primary_key=True)
    course_code = db.Column(db.String(20))
    course_name = db.Column(db.String(50))
    versions = db.relationship('CurriculumVersion', backref='version', lazy='dynamic')
    cohorts = db.relationship('Cohort', backref='cohort', lazy='dynamic')


    def __repr__(self):
        return '#%d Course Code: %s, Course Name: %s' %(self.id, self.course_code, self.course_name)

任何帮助都将不胜感激!

EN

回答 2

Stack Overflow用户

回答已采纳

发布于 2013-07-20 12:42:39

此错误:

代码语言:javascript
运行
复制
Could not determine join condition between parent/child tables on relationship CurriculumVersion.enrollments 

意味着SQLAlchemy在Enrollments中找不到合适的列来用作关系中的外键。

您定义了外键,但使用了不正确的表名。Flask-SQLAlchemy在创建表时将CamelCase类转换为camel_case,因此您需要更改以下内容:

代码语言:javascript
运行
复制
class Enrollment(db.Model, AuthUser):
    # ...
    version_id = db.Column(db.Integer, db.ForeignKey('curriculumversion.id'))
    #...

要这样做:

代码语言:javascript
运行
复制
class Enrollment(db.Model, AuthUser):
    # ...
    version_id = db.Column(db.Integer, db.ForeignKey('curriculum_version.id'))
    #...

或者,您可以使用__tablename__属性来覆盖Flask-SQLAlchemy使用的默认命名约定。

票数 33
EN

Stack Overflow用户

发布于 2013-07-20 03:57:59

尝试在您的CurriculumVersion类中使用primaryjoin,如下所示:

变化

代码语言:javascript
运行
复制
enrollments = db.relationship('Enrollment', backref='enrollment', lazy='dynamic')

代码语言:javascript
运行
复制
enrollments = db.relationship('Enrollment', backref='enrollment', lazy='dynamic', primaryjoin="Enrollment.version_id==CurriculumVersion.id")

注意:您可能也需要对其他类执行此操作。

票数 2
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/17753667

复制
相关文章

相似问题

领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档