Assembly.Load 3 dlls
Assembly.Load 3 dlls
提问于 2015-01-29 07:37:29
我有3个动态链接库加载到资源。它们作为嵌入式资源进行切换。我有这样的代码，只加载一个dll到汇编。如何加载所有的dll？
public partial class Main : Form
{
public Main()
{
AppDomain.CurrentDomain.AssemblyResolve += AssemblyResolve;
InitializeComponent();
}
public static Assembly AssemblyResolve(object sender, ResolveEventArgs args)
{
Assembly assembly = Assembly.GetExecutingAssembly();
using (Stream stream = assembly.GetManifestResourceStream(assembly.GetManifestResourceNames()[3]))
{
if (stream == null)
return null;
byte[] rawAssembly = new byte[stream.Length];
stream.Read(rawAssembly, 0, (int)stream.Length);
return Assembly.Load(rawAssembly);
}
}回答 1
Stack Overflow用户
发布于 2015-01-29 07:44:11
你正在调用索引3(奇怪的是，它不会失败，因为你有3个dll，它们应该放在2。也许是因为你除了dll之外还有一个资源？无论如何，你可以只做一个简单的循环。
for (int i = 1; i <= 3; i++) // Your dll's seem to be stored from index 1
using (Stream stream = assembly.GetManifestResourceStream(assembly.GetManifestResourceNames()[i]))
{
if (stream == null)
return null;
byte[] rawAssembly = new byte[stream.Length];
stream.Read(rawAssembly, 0, (int)stream.Length);
return Assembly.Load(rawAssembly);
}这样就可以了。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/28204497
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