问python pandas datetime.time - datetime.time

EN

import pandas as pd
import io
data = """col1                 col2
02:10:00.008209    02:08:38.053145
02:10:00.567054    02:08:38.053145
02:10:00.609842    02:08:38.053145
02:10:00.728153    02:08:38.053145
02:10:02.394408    02:08:38.053145"""
df = pd.read_table(io.BytesIO(data), delim_whitespace=True)
df2 = df.apply(pd.to_timedelta)
diff = df2.col1 - df2.col2

diff.astype("i8")/1e9

0    81.955064
1    82.513909
2    82.556697
3    82.675008
4    84.341263
dtype: float64

df.applymap(time.isoformat).apply(pd.to_timedelta)

In [71]: df2 = df.applymap(lambda x: ((x.hour*60+x.minute)*60+x.second)*10**6+x.microsecond)

In [72]: df2
Out[72]: 
         col1        col2
0  7800008209  7718053145
1  7800567054  7718053145

In [73]: df2['col1']-df2['col2']
Out[73]: 
0    81955064
1    82513909
dtype: int64

In [30]: df
Out[30]: 
                       0                          1
0 2014-02-28 13:30:19.926778 2014-02-28 13:30:47.178474
1 2014-02-28 13:30:29.814575 2014-02-28 13:30:51.183349

 df[0] - df[1]


 Out[31]: 
 0   -00:00:27.251696
 1   -00:00:21.368774
 dtype: timedelta64[ns]

(df[0] - df[1]).apply(lambda x : x.astype('timedelta64[us]')) #no actual difference when displayed

(df[0] - df[1]).apply(lambda x : x.astype('timedelta64[us]').astype('int'))

 0   -27251696000
 1   -21368774000
 dtype: int64

(df[0] - df[1]).astype('timedelta64[us]')

(df[0] - df[1]).astype('timedelta64[us]').astype('int')