我是sqlite数据库和iphone开发的新手
am将数据插入数据库,格式为
am insert description string is like dz
• 500 grams Chicken breasts
• 6-8 nos. Green chillies
• 2 tblsp Coriander leaves
• 2 tblsp Mint leaves
• 12 nos. Garlic
• 8-10 nos. Almonds
• 3/4 cup Fresh cream
• 1 inch Ginger
• 1 tblsp Lemon juice
• Oil
• Salt
this is code for inserting
-(void)insertDataToFavourites:(int)pageid111 :(NSString *)description
{
NSLog(@"%@",description);
const char *sqlStatement = "INSERT INTO AddFavoritenew (Id,Description) VALUES (?,?)";
sqlite3_stmt *compiled_statement;
if(sqlite3_prepare_v2(database, sqlStatement, -1, &compiled_statement, NULL) == SQLITE_OK)
{
sqlite3_bind_int(compiled_statement, 1, pageid111);
sqlite3_bind_text(compiled_statement, 2, [description UTF8String] , -1, SQLITE_TRANSIENT);
[ArrAddData addObject:[NSString stringWithFormat:@"%d", pageid111]];
NSLog(@"ArrAddData record is:--> %@",ArrAddData);
}
if(sqlite3_step(compiled_statement) != SQLITE_DONE )
{
// NSLog( @"Error: %s", sqlite3_errmsg(database) );
UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Alert!"
message:@"alerady you added this sms to favorite list."
delegate:self
cancelButtonTitle:@"Ok"
otherButtonTitles:nil, nil];
[alert show];
[alert release];
}
else
{
// NSLog( @"Insert into row id = %lld", sqlite3_last_insert_rowid(database));
UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Alert!"
message:@"Data saved to Favorite."
delegate:self
cancelButtonTitle:@"Ok"
otherButtonTitles:nil, nil];
[alert show];
[alert release];
}
sqlite3_finalize(compiled_statement);
}
我将上面的数据插入到数据库中,但问题是
当我显示从数据库中保存的数据时,它是否显示为
• 500 grams Chicken breasts
• 6-8 nos. Green chillies
• 2 tblsp Coriander leaves
• 2 tblsp Mint leaves
• 12 nos. Garlic
• 8-10 nos. Almonds
• 3/4 cup Fresh cream
• 1 inch Ginger
• 1 tblsp Lemon juice
• Oil
• Salt
获取错误列表代码为
-(void)getFavoriteList
{
if([ArrFav count] > 0)
[ArrFav removeAllObjects];
ArrFav = [[NSMutableArray alloc] init];
sqlite3_stmt *selectStatement=nil;
const char *sql ="SELECT Description FROM AddFavoritenew";
int returnvalue;
returnvalue = sqlite3_prepare_v2(database, sql, -1, &selectStatement, NULL);
if(returnvalue==1)
{
NSAssert1(0, @"Error: failed to select the database with message '%s'.", sqlite3_errmsg(database));
}
if(returnvalue == SQLITE_OK)
{
while(sqlite3_step(selectStatement) == SQLITE_ROW)
{
char *str = (char *)sqlite3_column_text(selectStatement,0);
[ArrFav addObject:[NSString stringWithFormat:@"%s",str]];
NSLog(@"Favorite data is:--> %s",str);
}
// NSLog(@"Favorite data is:--> %@",ArrFav);
}
}
请注意,我的数据库描述是text数据类型,....am也尝试使用varchar2数据类型
但是我想要像save data ..please这样的输出帮助我
致谢和问候
发布于 2012-10-09 20:59:51
初始字符串为UTF8。
您正在使用下面的代码从数据库重新创建它
[ArrFav addObject:[NSString stringWithFormat:@"%s",str]];
它只是使用naive ascii ( %s
格式说明符)转换str
尝试这样做,强制它使用UTF-8来解码字符串:
[ArrFav addObject:[[NSString alloc] initWithCString:str encoding:NSUTF8StringEncoding]];
发布于 2012-10-09 21:01:45
如果你只关心•
符号,这是最简单的解决方案。
//Convert • symbole with some different symbole that SQLite DB allowing
- (NSString *) convertToDBFormat:(NSString *)str
{
NSString *temp = [str stringByReplacingOccuranceOfStrings:@"•" withString:@"!~!"];
return temp;
}
//Convert back to origional format after retrieving from SQLite DB
- (NSString *) convertBackMyFormat:(NSString *)str
{
NSString *temp = [str stringByReplacingOccuranceOfString:@"!~!" withString:@"•"];
return temp;
}
您可以使用不属于字符串的任何符号来代替!~!
!:)
https://stackoverflow.com/questions/12800519
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