点击打开题目
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 16459 Accepted Submission(s): 7292
Problem Description
Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,can you find its solution between 0 and 100; Now please try your lucky.
Input
The first line of the input contains an integer T(1<=T<=100) which means the number of test cases. Then T lines follow, each line has a real number Y (fabs(Y) <= 1e10);
Output
For each test case, you should just output one real number(accurate up to 4 decimal places),which is the solution of the equation,or “No solution!”,if there is no solution for the equation between 0 and 100.
Sample Input
2
100
-4
Sample Output
1.6152
No solution!
Author
Redow
注意特判和卡精度就行了。
代码如下:
#include <cstdio>
#include <cmath>
#define f(x) 8*pow(x,4)+7*pow(x,3)+2*pow(x,2)+3*x+6
int main()
{
double l,r,mid;
double y;
int u;
scanf ("%d",&u);
while (u--)
{
scanf ("%lf",&y);
if (y < 6 || y > f(100) + 6)
{
printf ("No solution!\n");
continue;
}
l = 0;
r = 100;
while (r - l > 1e-8) //精度卡大一点
{
mid = (r + l) / 2;
if (f(mid) > y)
r = mid;
else
l = mid;
}
printf ("%.4lf\n",l);
}
return 0;
}