Java 集合数据处理技巧：使用 Stream API 实现多种操作

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发布于 2025-02-26 14:22:38

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在 Java 开发中，对集合数据进行处理是非常常见的需求，例如去重、排序、分组、求和等。Java 8 引入的 Stream API 为我们提供了一种简洁、高效的方式来处理集合数据。本文将详细介绍如何使用 Stream API 实现多种集合数据处理操作，并给出相应的代码示例。

1. List 根据某个属性去重

在处理 List 数据时，有时需要根据对象的某个属性进行去重。可以使用 TreeSet 和 Stream 来实现这一功能。以下是示例代码：


import java.util.ArrayList;
import java.util.Comparator;
import java.util.List;
import java.util.TreeSet;
import java.util.stream.Collectors;

// 定义 SKU 类
class SKU {
    private String gid;

    public SKU(String gid) {
        this.gid = gid;
    }

    public String getGid() {
        return gid;
    }
}

publicclass ListDistinctByProperty {
    public static void main(String[] args) {
        List<SKU> skuList = new ArrayList<>();
        skuList.add(new SKU("1"));
        skuList.add(new SKU("2"));
        skuList.add(new SKU("1"));

        ArrayList<SKU> skus = skuList.stream().collect(
                Collectors.collectingAndThen(
                        Collectors.toCollection(
                                () -> new TreeSet<>(Comparator.comparing(SKU::getGid))
                        ), ArrayList::new
                )
        );

        skus.forEach(sku -> System.out.println(sku.getGid()));
    }
}

在上述代码中，首先创建了一个 SKU 类，包含 gid 属性。然后使用 Stream 对 skuList 进行处理，通过 Collectors.toCollection 将其转换为 TreeSet，利用 TreeSet 的特性根据 gid 去重，最后再将 TreeSet 转换为 ArrayList。

2. 指定字段排序 2.1 升序排序

可以使用 Stream 的 sorted 方法和 Comparator.comparing 来实现指定字段的升序排序。以下是示例代码：


import java.util.ArrayList;
import java.util.Comparator;
import java.util.List;
import java.util.stream.Collectors;

// 定义 Order 类
class Order {
    privatelong createTime;

    public Order(long createTime) {
        this.createTime = createTime;
    }

    public long getCreateTime() {
        return createTime;
    }
}

publicclass ListSortAsc {
    public static void main(String[] args) {
        List<Order> orderList = new ArrayList<>();
        orderList.add(new Order(3));
        orderList.add(new Order(1));
        orderList.add(new Order(2));

        List<Order> sortedList = orderList.stream()
               .sorted(Comparator.comparing(Order::getCreateTime))
               .collect(Collectors.toList());

        sortedList.forEach(order -> System.out.println(order.getCreateTime()));
    }
}

2.2 降序排序

如果需要降序排序，只需在 Comparator.comparing 后调用 reversed 方法。以下是示例代码：


import java.util.ArrayList;
import java.util.Comparator;
import java.util.List;
import java.util.stream.Collectors;

// 定义 Order 类
class Order {
    privatelong createTime;

    public Order(long createTime) {
        this.createTime = createTime;
    }

    public long getCreateTime() {
        return createTime;
    }
}

publicclass ListSortDesc {
    public static void main(String[] args) {
        List<Order> orderList = new ArrayList<>();
        orderList.add(new Order(3));
        orderList.add(new Order(1));
        orderList.add(new Order(2));

        List<Order> sortedList = orderList.stream()
               .sorted(Comparator.comparing(Order::getCreateTime).reversed())
               .collect(Collectors.toList());

        sortedList.forEach(order -> System.out.println(order.getCreateTime()));
    }
}

2.3 null 排前面

如果需要将 null 值排在前面，可以使用 Comparator.nullsFirst 方法。以下是示例代码：


import java.util.ArrayList;
import java.util.Comparator;
import java.util.Date;
import java.util.List;
import java.util.stream.Collectors;

// 定义 LuckyBoysVo 类
class LuckyBoysVo {
    private Date usageTime;

    public LuckyBoysVo(Date usageTime) {
        this.usageTime = usageTime;
    }

    public Date getUsageTime() {
        return usageTime;
    }
}

publicclass ListSortNullFirst {
    public static void main(String[] args) {
        List<LuckyBoysVo> luckyBoysList = new ArrayList<>();
        luckyBoysList.add(new LuckyBoysVo(new Date(2000)));
        luckyBoysList.add(new LuckyBoysVo(null));
        luckyBoysList.add(new LuckyBoysVo(new Date(1000)));

        List<LuckyBoysVo> luckyBoysVoList = luckyBoysList.stream()
               .sorted(Comparator.comparing(LuckyBoysVo::getUsageTime, Comparator.nullsFirst(Date::compareTo)))
               .collect(Collectors.toList());

        luckyBoysVoList.forEach(vo -> System.out.println(vo.getUsageTime()));
    }
}

3. 指定字段相同，指定值计算和

可以使用 Collectors.groupingBy 方法对数据进行分组，然后使用 reduce 方法计算相同字段对应的值的和。以下是示例代码：


import java.util.ArrayList;
import java.util.List;
import java.util.stream.Collectors;

// 定义 ExportAgentVo 类
class ExportAgentVo {
    private String dealCode;
    private String agentId;
    private String goodsId;
    private String goodName;
    privateint count;
    private String name;
    private String address;

    public ExportAgentVo(String dealCode, String agentId, String goodsId, String goodName, int count, String name, String address) {
        this.dealCode = dealCode;
        this.agentId = agentId;
        this.goodsId = goodsId;
        this.goodName = goodName;
        this.count = count;
        this.name = name;
        this.address = address;
    }

    public String getDealCode() {
        return dealCode;
    }

    public String getAgentId() {
        return agentId;
    }

    public String getGoodsId() {
        return goodsId;
    }

    public String getGoodName() {
        return goodName;
    }

    public int getCount() {
        return count;
    }

    public String getName() {
        return name;
    }

    public String getAddress() {
        return address;
    }
}

publicclass ListSumByField {
    public static void main(String[] args) {
        List<ExportAgentVo> exportAgentVoList = new ArrayList<>();
        exportAgentVoList.add(new ExportAgentVo("1", "A", "G1", "Good1", 10, "Name1", "Addr1"));
        exportAgentVoList.add(new ExportAgentVo("2", "A", "G1", "Good1", 20, "Name1", "Addr1"));
        List<ExportAgentVo> exportAgentVoListResult = new ArrayList<>();

        exportAgentVoList.stream()
               .collect(Collectors.groupingBy(o -> (o.getGoodsId() + o.getAgentId()), Collectors.toList()))
               .forEach((id, transfer) -> {
                    transfer.stream()
                           .reduce((a, b) ->
                                    new ExportAgentVo(a.getDealCode(),
                                            a.getAgentId(),
                                            a.getGoodsId(),
                                            a.getGoodName(),
                                            a.getCount() + b.getCount(), a.getName(), a.getAddress())
                            )
                           .ifPresent(exportAgentVoListResult::add);
                });

        exportAgentVoListResult.forEach(vo -> System.out.println(vo.getCount()));
    }
}

4. 指定字段相同，计算相同个数

可以使用 Collectors.groupingBy 和 Collectors.counting 方法来计算指定字段相同的个数。以下是示例代码：


import java.util.ArrayList;
import java.util.List;
import java.util.Map;
import java.util.stream.Collectors;

// 定义 TkDetailMaskLayerMapping 类
class TkDetailMaskLayerMapping {
    private String maskId;

    public TkDetailMaskLayerMapping(String maskId) {
        this.maskId = maskId;
    }

    public String getMaskId() {
        return maskId;
    }
}

publicclass ListCountByField {
    public static void main(String[] args) {
        List<TkDetailMaskLayerMapping> list = new ArrayList<>();
        list.add(new TkDetailMaskLayerMapping("M1"));
        list.add(new TkDetailMaskLayerMapping("M1"));
        list.add(new TkDetailMaskLayerMapping("M2"));

        Map<String, Long> map = list.stream()
               .collect(Collectors.groupingBy(TkDetailMaskLayerMapping::getMaskId, Collectors.counting()));

        map.forEach((key, value) -> System.out.println(key + ": " + value));
    }
}

5. 指定字段分组

可以使用 Collectors.groupingBy 方法对 List 进行指定字段分组。以下是示例代码：


import java.util.ArrayList;
import java.util.List;
import java.util.Map;
import java.util.stream.Collectors;

// 定义 ExportAgentVo 类
class ExportAgentVo {
    private String agentId;

    public ExportAgentVo(String agentId) {
        this.agentId = agentId;
    }

    public String getAgentId() {
        return agentId;
    }
}

publicclass ListGroupByField {
    public static void main(String[] args) {
        List<ExportAgentVo> exportAgentVoListResult = new ArrayList<>();
        exportAgentVoListResult.add(new ExportAgentVo("A1"));
        exportAgentVoListResult.add(new ExportAgentVo("A2"));
        exportAgentVoListResult.add(new ExportAgentVo("A1"));

        Map<String, List<ExportAgentVo>> exportAgentVoMap = exportAgentVoListResult.stream()
               .collect(Collectors.groupingBy(ExportAgentVo::getAgentId));

        exportAgentVoMap.forEach((key, value) -> System.out.println(key + ": " + value.size()));
    }
}

6. 分组并求和

可以使用 Collectors.groupingBy 和 Collectors.summingInt 方法对数据进行分组并求和。以下是示例代码：


import java.util.ArrayList;
import java.util.List;
import java.util.Map;
import java.util.stream.Collectors;

// 定义 ExportGoodsProcurementDetailVo 类
class ExportGoodsProcurementDetailVo {
    private String supplierName;
    private String agentId;
    private String goodsId;
    privateint count;

    public ExportGoodsProcurementDetailVo(String supplierName, String agentId, String goodsId, int count) {
        this.supplierName = supplierName;
        this.agentId = agentId;
        this.goodsId = goodsId;
        this.count = count;
    }

    public String getSupplierName() {
        return supplierName;
    }

    public String getAgentId() {
        return agentId;
    }

    public String getGoodsId() {
        return goodsId;
    }

    public int getCount() {
        return count;
    }
}

publicclass ListGroupAndSum {
    public static void main(String[] args) {
        List<ExportGoodsProcurementDetailVo> goodsProcurementDetailVos = new ArrayList<>();
        goodsProcurementDetailVos.add(new ExportGoodsProcurementDetailVo("S1", "A1", "G1", 10));
        goodsProcurementDetailVos.add(new ExportGoodsProcurementDetailVo("S1", "A1", "G1", 20));
        ExportGoodsProcurementDetailVo exportGoodsProcurementDetailVo = new ExportGoodsProcurementDetailVo("S1", "A1", "", 0);
        ExportGoodsProcurementDetailVo exportGoBeerVo = new ExportGoodsProcurementDetailVo("", "A1", "", 0);

        Map<String, Integer> goodCountMap = goodsProcurementDetailVos.stream()
               .filter(a -> a.getSupplierName().equals(exportGoodsProcurementDetailVo.getSupplierName())
                        && a.getAgentId().equals(exportGoBeerVo.getAgentId()))
               .collect(Collectors.groupingBy(ExportGoodsProcurementDetailVo::getGoodsId,
                        Collectors.summingInt(ExportGoodsProcurementDetailVo::getCount)));

        goodCountMap.forEach((key, value) -> System.out.println(key + ": " + value));
    }
}

7. List 转 Map

可以使用 Collectors.toMap 方法将 List 转换为 Map。需要注意的是，如果集合对象有重复的 key，会报错 Duplicate key，可以使用 (k1, k2) -> k1 来处理重复 key 的情况。以下是示例代码：


import java.util.ArrayList;
import java.util.List;
import java.util.Map;
import java.util.stream.Collectors;

// 定义 CustomerDetailResp 类
class CustomerDetailResp {
    private String dept;
    private String members;

    public CustomerDetailResp(String dept, String members) {
        this.dept = dept;
        this.members = members;
    }

    public String getDept() {
        return dept;
    }

    public String getMembers() {
        return members;
    }
}

// 定义 Apple 类
class Apple {
    privateint id;

    public Apple(int id) {
        this.id = id;
    }

    public int getId() {
        return id;
    }
}

publicclass ListToMap {
    public static void main(String[] args) {
        List<CustomerDetailResp> result = new ArrayList<>();
        result.add(new CustomerDetailResp("D1", "M1"));
        result.add(new CustomerDetailResp("D2", "M2"));

        Map<String, String> map1 = result.stream().collect(Collectors.toMap(CustomerDetailResp::getDept, CustomerDetailResp::getMembers));
        Map<String, CustomerDetailResp> map2 = result.stream().collect(Collectors.toMap(CustomerDetailResp::getDept, CustomerDetailResp -> CustomerDetailResp));

        List<Apple> appleList = new ArrayList<>();
        appleList.add(new Apple(1));
        appleList.add(new Apple(1));
        Map<Integer, Apple> appleMap = appleList.stream().collect(Collectors.toMap(Apple::getId, a -> a, (k1, k2) -> k1));
    }
}

8. List 转 String

可以使用 Google Guava 库的 Joiner 类将 List 转换为 String。以下是示例代码：


import com.google.common.base.Joiner;
import java.util.ArrayList;
import java.util.List;

publicclass ListToString {
    public static void main(String[] args) {
        List<String> itemNoList = new ArrayList<>();
        itemNoList.add("1");
        itemNoList.add("2");
        itemNoList.add("3");

        String join = Joiner.on(',').join(itemNoList);
        System.out.println(join);
    }
}

9. String 转 List

可以使用 Arrays.stream 和 Collectors.toList 方法将 String 转换为 List。以下是示例代码：


import java.util.Arrays;
import java.util.List;
import java.util.stream.Collectors;

public class StringToList {
    public static void main(String[] args) {
        String sales = "1,2,3,2";
        List<String> saleList = Arrays.stream(sales.split(",")).distinct().collect(Collectors.toList());
        saleList.forEach(System.out::println);
    }
}

通过以上示例，我们可以看到 Java 8 的 Stream API 为集合数据处理提供了非常强大和便捷的功能。合理使用这些功能可以大大提高代码的可读性和开发效率。本文示例已涵盖日常开发中90%的集合处理场景，建议根据具体业务需求灵活组合使用。对于更复杂的操作，可结合Collectors.joining、mapping等收集器实现。

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原始发表：2025-02-25，如有侵权请联系 cloudcommunity@tencent.com 删除

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