Python中21道个程序小练习

name = 'ABDMLBM'
height = 175
weight = 140

# "My name is 'Nick', my height is 180, my weight is 140"
print('My name is %s,my height is %s,my weight is %s'%(name,height,weight))
print('My name is {},my height is {},my weight is {}'.format(name,height,weight))
print(f'My name is {name},my height is {height},my weight is {weight}')

while True:
    girl_age =int( input('输入美女年龄'))
    if girl_age < 18:
        print('不接受未成年')
    elif girl_age >= 18 and girl_age < 25:
        print('心动表白')
    elif girl_age >= 25 and girl_age < 45:
        print('阿姨好')
    else :
        print('奶奶好')

i = 1
while i < 101:
    oi = i % 2
    if oi == 0:
        print(i)
    i += 1

age = 25
count = 0
while count < 4:
    user_age = int(input('请输入你的年龄：'))
    if user_age == age:
        print('你猜对了')
        break
    elif user_age > age:
        print('你猜大了')
    else:
        print('你猜小了')
    count += 1
    if count != 3 :
        continue
    else:
        print('你已经猜了三次，答"Y"或者"y"还想再玩，答"N"或者"n"退出')
        user_player = input('请输入：')
        if user_player == "Y" or user_player == "y":
            count = 0
        else:
            break

s = 'hello alex alex say hello sb sb'
l=s.split()
print(l)
dic = {}
for item in l:
    if item in dic:
        dic[item]=dic[item]+1
    else:
        dic[item]=1
print(dic)

from collections import Counter
import re
with open('a.txt', 'r', encoding='utf-8') as f:
    txt = f.read()
c = Counter(re.split('\W+',txt))  #取出每个单词出现的个数
print(c)
ret = c.most_common(10)   #取出频率最高的前10个
print(ret)

def mao_pao(li):
    for i in range(len(li)):
        for j in range(len(li)):
            if li[i] < li[j]:
                li[i],li[j] = li[j] ,li[i]
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import random
li = list(range(10))
random.shuffle(li)
print(li)
mao_pao(li)
print(li) 

#方式一
li = [1,5,5,4,12,3,1,5]
print(list(set(l)))

#方式二
li = [1,5,5,4,12,3,1,5]
def func(li):
    l = []
    for i in li:
        if i not in l:
            l.append(i)
    return l
print(func(li)) 

#方式一：递归版
li = [1,2,3,4,5,6,7,8,9,10]
def erfen(li,aim ,start=0 ,end=len(li)-1):
    if start <= end:
        mid = (start+end)//2
        if li[mid] >aim :  #如果中间的值比目标值大，就从左边找
            return erfen(li,aim,start,mid-1)
        elif li[mid]<aim : #从右边找
            return erfen(li,aim,mid+1,end)
        else:
            return mid
ret = erfen(li,10)
print(ret)

#方式二：循环版
li = [1,2,3,4,5,6,7,8,9,10]
def erfen(li,aim,start=0,end=len(li)-1):
    while start <= end:
        mid = (start+end) //2
        if li[mid] < aim:
            start = li[mid] +1
        elif li[mid] >aim:
            end = li[mid] -1
        else:
            return mid

print(erfen(li,10)) 

def f(x,l=[]):
    for i in range(x):
        l.append(i*i)
    print(l)
f(2)  #[0,1]
f(3,[3,2,1]) #[3,2,1,0 1 4]
f(3) #[0,1,0,1,4]

# 方式一
def str_reverse(str):
    return str[::-1]  #从前到后步长为-1
print(str_reverse('string'))

# 方式二
def str_reverse2(str):
    l = list(str)
    l.reverse()
    new_str = ''.join(l)
    return new_str
print(str_reverse2('string')) 

# 0 1 2 3 4
# 0   5   7
sums=sum(map(lambda x:x+3,list(range(5))[::2]))
print(sums) 

List=[-2,1,3,-6]
List.sort(key=abs)  #按照绝对值从小到大排序
print(List) 

import datetime
data = '20170130'
def func(n,data):

    date=datetime.datetime.strptime(data,'%Y%m%d')
    da=datetime.timedelta(n)
    return date+da

print(func(2,data)) 

import os
def print_code():
    with open(os.path.join(os.getcwd(),__file__),'r',encoding='utf-8') as f:
        return f.read()
print(print_code()) 

# 方式一
list1 = [1,2,3,5,8,4,2,6]
list2 = [11,44,21,2,54,77]
print(list(set(list1+list2)))
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#方式二
list1.extend(list2)
print(list(set(list1)))
#方式三
def list_union(list1,list2):
    for i in list2:
        list1.append(i)
    return list1
print(list(set(list_union(list1,list2)))) 

alist = [{'name': 'a', 'age': 20}, {'name': 'b', 'age': 30}, {'name': 'c', 'age': 25}]
alist.sort(key=lambda x:x['age'],reverse=True)
print(alist) 

s = "k:1|k1:2|k2:3|k3:4"
str_list = s.split('|')
print(str_list)
d = {}
for i in str_list:
    key ,value = i.split(':')
    d[key] = value
print(d) 

def fib(n):
    if n<=2:
        return 1
    else:
        return fib(n-1) + fib(n-2)
print(fib(10))