Python创建培根密码表_实现培根密码解密
Python创建培根密码表_实现培根密码解密
python实现解密培根脚本，解密程序好多都是在线的，今天想把解密程序用python写一个离线的，就当学习练习，以下文章供大家参考、学习，如有错误，多多指出，谢谢大家！
- 常规培根密码表：明文 i和j、u和v 所对应的密文是一样的。
- 扩展培根密码表：包括所有26个字符。
- 培根密码解密：5个字符为一组为一个明文密码字符
培根密码表一
["aaaaa","aaaab","aaaba","aaabb","aabaa","aabab","aabba","aabbb","abaaa","abaab","ababa","ababb","abbaa","abbab","abbba","abbbb","baaaa","baaab","baaba","baabb","babaa","babab","babba","babbb","bbaaa","bbaab"]
- 26个密文，分别对应明文26个英文字母（不区分大小写）。
- 要求编写一个解密脚本，并用这个脚本来解密下面的密文：
BAABAABBAAAAAAAABABBABABBBAABABAABBABBBAABBABAABAA
#!/usr/bin/python3
txt = input().lower() #.lower()方法把输入数据转换为小写
#a定义为键
a = ["aaaaa","aaaab","aaaba","aaabb","aabaa","aabab","aabba","aabbb","abaaa","abaab","ababa","ababb","abbaa","abbab","abbba","abbbb","baaaa","baaab","baaba","baabb","babaa","babab","babba","babbb","bbaaa","bbaab"]
#b定义为值，并利用列表推导式列出a~z
b = [chr(i) for i in range(ord('a'),ord('z')+1)]
['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
key = dict(zip(a,b)) #key定义为字典，使用zip()函数将a,b组合为字典
for i in range(0,len(txt),5): #0~50，共计50字符，步长为5
print(key.get(txt[i:i+5]),end='') #输出字典对应的值，不换行培根密码表二
["aaaaa","aaaab","aaaba","aaabb","aabaa","aabab","aabba","aabbb","abaaa","abaab","ababa","ababb","abbaa","abbab","abbba","abbbb","baaaa","baaab","baaba","baabb","babaa","babab","babba","babbb"]
24个密文，对应的明文：
['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', '(ij)', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', '(uv)', 'w', 'x', 'y', 'z’]
要求编写一个解密脚本，并用这个脚本来解密下面的密文：
AAAABAAAAAAAABAABBABABBAAABAAABAAABABBAAABBABBAABAAABABABBABABBABAAABB
#!/usr/bin/python3
#用replace()方法和lower()方法处理输入数据，去除两侧空格并把字符转换成小写
txt = input().replace(' ','').lower()
a = ["aaaaa","aaaab","aaaba","aaabb","aabaa","aabab","aabba","aabbb","abaaa","abaab","ababa","ababb","abbaa","abbab","abbba","abbbb","baaaa","baaab","baaba","baabb","babaa","babab","babba","babbb"]
b = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', '(ij)', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', '(uv)', 'w', 'x', 'y', 'z']
#使用字典推导式将a与b组成对应的字典
key = {i:j for i,j in zip(a,b)}
#循环变量i步长为5进行取值
for i in range(0,len(txt),5):
print(key.get(txt[i:i+5]),end='')解密练习：
密文：hellOeveryone,AreYOU huNGrY?woUldyou li To eAtBAcon?
- 正规的培根密文密码，一般大写字母对应a，小写字母对应b，否则反之。
- 上边已经做好了两个解密脚本，只需将对应的字符进行转换成abab这样的字符串
>>> a = 'hellOeveryone,AreYOU huNGrY?woUldyou li To eAtBAcon?'
>>> flag = ''
>>> for i in a:
... if i.islower(): #如果i小写，则flag变量追加a
... flag = flag + 'a'
... elif i.isupper(): #如果i是小写，则flag变量追加b
... flag = flag + 'b'
...
>>> flag #拿最后的值去进行解密
'aaaabaaaaaaaabaabbbaabbabaabaaaaaaabaababbaaa'
提示：
若两次解密都错误，或许是 a b 的值对应错了。 可以使用
table = ' '.maketrans('ab','ba')
flag.translate(table)则可以进行a与b的互换
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