c++将十进制数转化为二进制数_十六进制小数转二进制

#include "stdafx.h"
#include <iostream>
#include <math.h>




using namespace std;
void change(double x);


void change(double x)
{
	double n = 0;                                            //x为输入的纯小数
	int i = 0;                                          //n为每次x*2取得的得数
	int j = 0;
	int a[8];
	for (int i = 0; i < 8; i++)
	{
		a[i] = 0;
	}
	if (x<0) {
		x = -x;
		j = 1;
	}
	while (i<8)
	{
		int k;
		n = x * 2;
		k =floor(n);
		a[i] = k;
		x = n - k;
		i = i + 1;
		
	}
	if (j == 1)
	{
		cout << "-.";
	}
	else
	{
		cout << "+.";
	}
	for (int k = 0; k < 8;)
	{
		for (int l = 0; l < 4; l++)
		{
			cout << a[k];
			k++;
		}
		if (k != 8)
		{
			cout << " ";
		}
	}


}




int main()
{
	double n;
	while (cin >> n)                          //每当输入一个小数就做一次转换
	{
		change(n);
		cout << '\n';
	}
    return 0;
}