Python保留小数的方法

s= 12.3445
print('%.2f'%s)
# 12.34


s= 12.345
print('%.2f'%s)
# 12.35

s= 12.345
a = round(s,2)
print(a)
#12.35

s= 12.3445
a = round(s,2)
print(a)
# 12.34

from decimal import Decimal
s = 12.3445
a = Decimal(s).quantize(Decimal('0.00'))
print(a)
#12.34


from decimal import Decimal
s = 12.345
a = Decimal(s).quantize(Decimal('0.00'))
print(a)
# 12.35

s = 12.345


a = str(s).split('.')
s1 = a[0]+'.'+a[1][:2]
print(s1)

import re
s= 12.345
a = re.findall(r"\d{1,}?\.\d{2}", str(s))
print(a[0])
# 12.34