[html]js无缝循环滚动图片示例代码

<!--轮播图-->
<div id="banner" >
  <ul>
    <li > <a href="YunNan.html"><img src="./微信图片_20200621003327.jpg"> 1</a></li>
    <li> <a href="Switzerland.html"><img src="./微信图片_20200621003339.png" >2</a></li>
    <li> <a href="XiZang1.html"><img src="./微信图片_20200621003335.jpg" > 3</a></li>
  </ul>
   
</div>

* { 
   
    margin: 0;
    padding: 0;
}
.btumm { 
   
    text-align: center;
    padding-top: 50%;
}
.btumm pic { 
   
color=#1d5983;
    size: 2;
}
#banner { 
   
    width: 100%;
    margin: 0;
    padding: 0;
    height: 600px;
    position: absolute;
    overflow: hidden;
}
#banner ul { 
   
    list-style: none;
    margin: 0;
    padding: 0;
    position: absolute;
    width: 1000px;
}
#banner ul li { 
   
    float: left;
    margin: 0;
    padding: 0;
}
#banner ul li img { 
   
    width: 400px;
    height: 600px;
}

//启动时方法
window.onload=function(){ 
   
var oDiv = document.getElementById('banner');
var oUl = oDiv.getElementsByTagName('ul')[0];
var Li = oUl.getElementsByTagName('li');
oUl.innerHTML = oUl.innerHTML+oUl.innerHTML;
oUl.style.width = Li[0].offsetWidth*Li.length+'px';//ul的宽度等于每个li的宽度乘以所有li的长度

var speed = 2
function move(){ 
   

if(oUl.offsetLeft<-oUl.offsetWidth/speed){ 
   

oUl.style.left = '0'

}

//如果右边横向滚动的距离大于0 就让他的位置回到一半

if(oUl.offsetLeft>0){ 
   

oUl.style.left = -oUl.offsetWidth/speed+'px';

}
oUl.style.left = oUl.offsetLeft+speed+'px';//进行右横向滚动
//oUl.style.left = oUl.offsetLeft-2+'px';//进行左横向滚动

}

//调用方法
var timer = setInterval(move,30)//速度

//鼠标悬停时暂停
oDiv.onmouseover=function(){ 
   

clearInterval(timer);

}

//鼠标离开之后恢复
oDiv.onmouseout=function(){ 
   

timer = setInterval(move,30)

}

}