c++学习笔记4，调用派生类的顺序构造和析构函数（一个）

//測试派生类的构造函数的调用顺序何时调用
//Fedora20 gcc version=4.8.2
#include <iostream>
using namespace std;

class base
{
public:
	base()
	{
		
		cout<<"base created!"<<endl;
	}
	~base()
	{
		cout<<"base destroyed!"<<endl;
	}
};
//公有继承
class A:public base
{
public:
	A()
	{
		cout<<"A created!"<<endl;
	}
	~A()
	{
		cout<<"A destroyed!"<<endl;
	}
};
class B:public A
{
public:
	B()
	{
		cout<<"B created!"<<endl;
	}
	~B()
	{
		cout<<"B destroyed!"<<endl;
	}
};

int main()
{
	A a;
	<span style="color:#ff0000;">A *a1;</span>
	cout<<"能够看到a1并没有调用基类的构造函数"<<endl;
	<span style="color:#ff0000;">A *a2=new A;</span>
	//仅仅有在new 一个对象的时候才会调用基类的构造函数
	cout<<"能够看到a3也并没有调用基类的构造函数"<<endl;
	A *a3=&a;

       B b;
}

int main()
{
	 A a[2];
}

int main()
{
	 A *a[2];
}

void fun()
	{
		cout<<"A fun run"<<endl;
	}

int main()
{
	 A *a[2];
	a[0]->fun();
}

class A:public base
{
public:
	int i;
	A()
	{
		cout<<"A created!"<<endl;
	}
	~A()
	{
		cout<<"A destroyed!"<<endl;
	}
	void fun()
	{
		cout<<"A fun run"<<endl;
	}
};

int main()
{
	 A *a[2];
	a[0]->fun();
	cout<<endl<<a[0]->i<<endl;
}