文章作者:Tyan 博客:noahsnail.com | CSDN | 简书
**解析:**Version 1,两层循环遍历,O(N^2)。
class Solution:
def maximumDifference(self, nums: List[int]) -> int:
length = len(nums)
diff = -1
for i in range(length):
for j in range(i+1, length):
if nums[j] > nums[i]:
diff = max(diff, nums[j] - nums[i])
return diff
**解析:**Version 2,从左向右遍历,minimum
始终保持左半部分最小值,如果当前数字num
比minimum
大,求二者的difference
,取difference
最大值,O(N)。
class Solution:
def maximumDifference(self, nums: List[int]) -> int:
length = len(nums)
diff = -1
minimum = nums[0]
for num in nums:
if num > minimum:
diff = max(diff, num - minimum)
minimum = min(minimum, num)
return diff