Python中相见恨晚的技巧

a, b = 5, 10
print(a, b)   //5, 10
a, b = b, a
print(a, b)   //10, 5

a = ['python', 'java', 'c++', 'go']
print(','.join(a))  //python,java,c++,go

a = [1, 1, 1, 2, 3, 3, 3, 3, 4, 4, 4]
print(max(set(a), key = a.count))

from collections import Counter

a = 'abcdefg'
b = 'adcbgfb'
print(Counter(a) == Counter(b))

a = 'dadabjdnakdmnkafad'
print(a[::-1])

num = 1343453535
print(int(str(num)[::-1]))

a = [1,3,554,64,2]
print(a[::-1])

origin = [['a', 'b'], ['c', 'd'], ['e', 'f']]
transposed = zip(*origin)
print(list(transposed ))

b = 6
print(4 < b < 7)
print(1 == b < 9)

b = 'B'
c = 'C'
flag = True
a = b if flag else c

def product(a, b):
   return a * b

def add(a, b):
   return a + b

b = True
print((product if b else add)(5 ,7))

a = [1, 2, 3, 4, 5]
for el in a:
    if(el == 0)
       print('找到 0 了')
else:
    print('没有找到 0')

d1 = {'a': 1}
d2 = {'b': 2}

print(**d1, **d2)  # python3.5支持

print(dict(d1.items() | d2.items()))

d1.update(d2)
print(d1)

items = [2,2,3,4,1]
print(list(set(items)))

dictionary = {'a': 1, 'b': 2}

def func(**kwargs)
  for key in kwargs:
     print('key:', key, 'value:',kwargs[key])

numbers = [1, 2, 3, 4, 5, 6]
y = [x for x in numbers if x % 2 == 0]
print(y)   //[2, 4, 6]

x = [1, 2, 3]
y = map(lambda x : x + 1 , x)
print(y)  //[2, 3, 4]