算法的重要性,我就不多说了吧,想去大厂,就必须要经过基础知识和业务逻辑面试+算法面试。所以,为了提高大家的算法能力,这个公众号后续每天带大家做一道算法题,题目就从LeetCode上面选 !
今天和大家聊的问题叫做 二维区域和检索 - 矩阵不可变,我们先来看题面:
https://leetcode-cn.com/problems/range-sum-query-2d-immutable/
给定 matrix = [
[3, 0, 1, 4, 2],
[5, 6, 3, 2, 1],
[1, 2, 0, 1, 5],
[4, 1, 0, 1, 7],
[1, 0, 3, 0, 5]
]
sumRegion(2, 1, 4, 3) -> 8
sumRegion(1, 1, 2, 2) -> 11
sumRegion(1, 2, 2, 4) -> 12
不看官方题解不知道,二维前缀和,了不起了不起。
class NumMatrix:
def __init__(self, matrix: List[List[int]]):
if not matrix:
return
m = len(matrix)
n = len(matrix[0])
self.p = [[0] * (n+1) for _ in range(m+1)]
for i in range(1, m+1):
for j in range(1, n+1):
self.p[i][j] = matrix[i-1][j-1] + self.p[i-1][j] + self.p[i][j-1] - self.p[i-1][j-1]
def sumRegion(self, row1: int, col1: int, row2: int, col2: int) -> int:
return self.p[row2+1][col2+1] - self.p[row1][col2+1] - self.p[row2+1][col1] + self.p[row1][col1]
class NumMatrix:
def __init__(self, matrix: List[List[int]]):
self._matrix = matrix
def sumRegion(self, row1: int, col1: int, row2: int, col2: int) -> int:
result = 0
"""
for row in self._matrix[row1:row2+1]:
for col in row[col1:col2+1]:
result += col
"""
for i in range(row1, row2+1):
for j in range(col1, col2+1):
result += self._matrix[i][j]
return result
好了,今天的文章就到这里,如果觉得有所收获,请顺手点个在看或者转发吧,你们的支持是我最大的动力 。