# 认为a1是全局的
a1 = 100
def fun():
print(a1)
print("I am in fun")
# a2的作用范围是fun
a2 = 99
print(a2)
print(a1)
fun()
# print(a2)100100I am in fun99def fun():
global b1
b1 = 100
print(b1)
print("I am in fun")
b2 = 99
print(b2)
fun()
print(b1)100I am in fun99100# globals 和 locals
# globals 和 locals 叫做内建函数
a = 1
b = 2
def fun(c,d):
e = 111
print("Locals={0}".format(locals()))
print("Globals={0}".format(globals()))
fun(100, 200)Locals={'c': 100, 'd': 200, 'e': 111}/*
* 提示:该行代码过长,系统自动注释不进行高亮。一键复制会移除系统注释
* Globals={'__name__': '__main__', '__doc__': 'Automatically created module for IPython interactive environment', '__package__': None, '__loader__': None, '__spec__': None, '__builtin__': <module 'builtins' (built-in)>, '__builtins__': <module 'builtins' (built-in)>, '_ih': ['', '# 认为a1是全局的\na1 = 100\n\ndef fun():\n print(a1)\n print("I am in fun")\n a2 = 99\n print(a2)\n \nprint(a2)', '# 认为a1是全局的\na1 = 100\n\ndef fun():\n print(a1)\n print("I am in fun")\n a2 = 99\n print(a2)\n \nprint(a1)', '# 认为a1是全局的\na1 = 100\n\ndef fun():\n print(a1)\n print("I am in fun")\n a2 = 99\n print(a2)\n \nprint(a1)\nfun()\n# print(a2)', '# 认为a1是全局的\na1 = 100\n\ndef fun():\n print(a1)\n print("I am in fun")\n a2 = 99\n print(a2)\n \nprint(a1)\nfun()\nprint(a2)', '# 认为a1是全局的\na1 = 100\n\ndef fun():\n print(a1)\n print("I am in fun")\n a2 = 99\n print(a2)\n \nprint(a1)\nfun()\n# print(a2)', 'def fun():\n b1 = 100\n print(b1)\n print("I am in fun")\n b2 = 99\n print(b2)\n \nfun()', 'def fun():\n global b1 = 100\n print(b1)\n print("I am in fun")\n b2 = 99\n print(b2)\n\nprint(b1)', 'def fun():\n global b1 \n b1 = 100\n print(b1)\n print("I am in fun")\n b2 = 99\n print(b2)\n\nprint(b1)', 'def fun():\n global b1 \n b1 = 100\n print(b1)\n print("I am in fun")\n b2 = 99\n print(b2)\n\nprint(b1)', 'def fun():\n global b1 \n b1 = 100\n print(b1)\n print("I am in fun")\n b2 = 99\n print(b2)\n\nprint(b1)', '# globals 和 locals\na = 1\nb = 2\n\ndef fun(c,d):\n e = 111\n print("Locals={0}".format(locals()))\n print("Globals={0}".format(globals())\n \nfun(100, 200)', '# globals 和 locals\na = 1\nb = 2\n\ndef fun(c,d):\n e = 111\n print("Locals={0}".format(locals()))\n print("Globals={0}".format(globals()))\n \nfun(100, 200)', '# globals 和 locals\n# globals 和 locals 叫做内建函数\na = 1\nb = 2\n\ndef fun(c,d):\n e = 111\n print("Locals={0}".format(locals()))\n print("Globals={0}".format(globals()))\n \nfun(100, 200)'], '_oh': {}, '_dh': ['d:\\Jupyter\\nootbook\\笔记'], 'In': ['', '# 认为a1是全局的\na1 = 100\n\ndef fun():\n print(a1)\n print("I am in fun")\n a2 = 99\n print(a2)\n \nprint(a2)', '# 认为a1是全局的\na1 = 100\n\ndef fun():\n print(a1)\n print("I am in fun")\n a2 = 99\n print(a2)\n \nprint(a1)', '# 认为a1是全局的\na1 = 100\n\ndef fun():\n print(a1)\n print("I am in fun")\n a2 = 99\n print(a2)\n \nprint(a1)\nfun()\n# print(a2)', '# 认为a1是全局的\na1 = 100\n\ndef fun():\n print(a1)\n print("I am in fun")\n a2 = 99\n print(a2)\n \nprint(a1)\nfun()\nprint(a2)', '# 认为a1是全局的\na1 = 100\n\ndef fun():\n print(a1)\n print("I am in fun")\n a2 = 99\n print(a2)\n \nprint(a1)\nfun()\n# print(a2)', 'def fun():\n b1 = 100\n print(b1)\n print("I am in fun")\n b2 = 99\n print(b2)\n \nfun()', 'def fun():\n global b1 = 100\n print(b1)\n print("I am in fun")\n b2 = 99\n print(b2)\n\nprint(b1)', 'def fun():\n global b1 \n b1 = 100\n print(b1)\n print("I am in fun")\n b2 = 99\n print(b2)\n\nprint(b1)', 'def fun():\n global b1 \n b1 = 100\n print(b1)\n print("I am in fun")\n b2 = 99\n print(b2)\n\nprint(b1)', 'def fun():\n global b1 \n b1 = 100\n print(b1)\n print("I am in fun")\n b2 = 99\n print(b2)\n\nprint(b1)', '# globals 和 locals\na = 1\nb = 2\n\ndef fun(c,d):\n e = 111\n print("Locals={0}".format(locals()))\n print("Globals={0}".format(globals())\n \nfun(100, 200)', '# globals 和 locals\na = 1\nb = 2\n\ndef fun(c,d):\n e = 111\n print("Locals={0}".format(locals()))\n print("Globals={0}".format(globals()))\n \nfun(100, 200)', '# globals 和 locals\n# globals 和 locals 叫做内建函数\na = 1\nb = 2\n\ndef fun(c,d):\n e = 111\n print("Locals={0}".format(locals()))\n print("Globals={0}".format(globals()))\n \nfun(100, 200)'], 'Out': {}, 'get_ipython': <bound method InteractiveShell.get_ipython of <ipykernel.zmqshell.ZMQInteractiveShell object at 0x000001B07AF18BA8>>, 'exit': <IPython.core.autocall.ZMQExitAutocall object at 0x000001B07D7398D0>, 'quit': <IPython.core.autocall.ZMQExitAutocall object at 0x000001B07D7398D0>, '_': '', '__': '', '___': '', '_i': '# globals 和 locals\na = 1\nb = 2\n\ndef fun(c,d):\n e = 111\n print("Locals={0}".format(locals()))\n print("Globals={0}".format(globals()))\n \nfun(100, 200)', '_ii': '# globals 和 locals\na = 1\nb = 2\n\ndef fun(c,d):\n e = 111\n print("Locals={0}".format(locals()))\n print("Globals={0}".format(globals())\n \nfun(100, 200)', '_iii': 'def fun():\n global b1 \n b1 = 100\n print(b1)\n print("I am in fun")\n b2 = 99\n print(b2)\n\nprint(b1)', '_i1': '# 认为a1是全局的\na1 = 100\n\ndef fun():\n print(a1)\n print("I am in fun")\n a2 = 99\n print(a2)\n \nprint(a2)', 'a1': 100, 'fun': <function fun at 0x000001B07D8C41E0>, '_i2': '# 认为a1是全局的\na1 = 100\n\ndef fun():\n print(a1)\n print("I am in fun")\n a2 = 99\n print(a2)\n \nprint(a1)', '_i3': '# 认为a1是全局的\na1 = 100\n\ndef fun():\n print(a1)\n print("I am in fun")\n a2 = 99\n print(a2)\n \nprint(a1)\nfun()\n# print(a2)', '_i4': '# 认为a1是全局的\na1 = 100\n\ndef fun():\n print(a1)\n print("I am in fun")\n a2 = 99\n print(a2)\n \nprint(a1)\nfun()\nprint(a2)', '_i5': '# 认为a1是全局的\na1 = 100\n\ndef fun():\n print(a1)\n print("I am in fun")\n a2 = 99\n print(a2)\n \nprint(a1)\nfun()\n# print(a2)', '_i6': 'def fun():\n b1 = 100\n print(b1)\n print("I am in fun")\n b2 = 99\n print(b2)\n \nfun()', '_i7': 'def fun():\n global b1 = 100\n print(b1)\n print("I am in fun")\n b2 = 99\n print(b2)\n\nprint(b1)', '_i8': 'def fun():\n global b1 \n b1 = 100\n print(b1)\n print("I am in fun")\n b2 = 99\n print(b2)\n\nprint(b1)', '_i9': 'def fun():\n global b1 \n b1 = 100\n print(b1)\n print("I am in fun")\n b2 = 99\n print(b2)\n\nprint(b1)', '_i10': 'def fun():\n global b1 \n b1 = 100\n print(b1)\n print("I am in fun")\n b2 = 99\n print(b2)\n\nprint(b1)', '_i11': '# globals 和 locals\na = 1\nb = 2\n\ndef fun(c,d):\n e = 111\n print("Locals={0}".format(locals()))\n print("Globals={0}".format(globals())\n \nfun(100, 200)', '_i12': '# globals 和 locals\na = 1\nb = 2\n\ndef fun(c,d):\n e = 111\n print("Locals={0}".format(locals()))\n print("Globals={0}".format(globals()))\n \nfun(100, 200)', 'a': 1, 'b': 2, '_i13': '# globals 和 locals\n# globals 和 locals 叫做内建函数\na = 1\nb = 2\n\ndef fun(c,d):\n e = 111\n print("Locals={0}".format(locals()))\n print("Globals={0}".format(globals()))\n \nfun(100, 200)'}
*/ eval(string_code, globals=None, locals=None) exec(string_code, globals=None, locals=None)x = 100
y = 200
# 执行x+y
# z = x + y
z1 = x + y
z2 = eval("x+y")
print(z1)
print(z2)300300# exec案例
x = 100
y = 200
# 执行x+y
# z = x + y
z1 = x + y
# 1. 注意字符串中引号的写法
# 2. 比对exec执行结果和代码执行结果
z2 = exec("print('x+y:',x+y)")
print(z1)
print(z2)x+y: 300300None# 递归调用深度限制代码
x = 0
def fun():
global x
x += 1
print(x)
# 函数自己调用自己
fun()
# 调用函数
# fun()---------------------------------------------------------------------------RecursionError Traceback (most recent call last)<ipython-input-23-bfedb7e396bc> in <module> 10 11 # 调用函数---> 12 fun()<ipython-input-23-bfedb7e396bc> in fun() 7 print(x) 8 # 函数自己调用自己----> 9 fun() 10 11 # 调用函数... last 1 frames repeated, from the frame below ...<ipython-input-23-bfedb7e396bc> in fun() 7 print(x) 8 # 函数自己调用自己----> 9 fun() 10 11 # 调用函数RecursionError: maximum recursion depth exceeded while calling a Python object# 斐波那契数列
# 一列数字,第一个值是1,第二个也是1,从第三个开始,每一个数字的值等于前两个数字出现的值的和
# 数学公式为: f(1) = 1, f(2) = 1, f(n) = f(n - 1) + f(n - 2)
# 例如: 1,1,2,3,5,8,13....
# n表示求第n个数字的斐波那契数列的值
def fib(n):
if n == 1 or n == 2:
return 1
elif n > 0:
return fib(n-1) + fib(n-2)
else:
return None
print(fib(3))
print(fib(5))
print(fib(10))
print(fib(-1))
print(fib(1))2555None1# 1. 创建空列表
l1 = []
# type是内置函数,负责打印出变量的类型
print(type(l1))
print(l1)
# 2. 创建带值的列表
l2 = [100]
print(type(l2))
print(l2)
# 3. 创建列表,带多个值
l3 = [2,3,5,5,9,7,8,]
print(type(l3))
print(l3)
# 4. 使用list()
l4 = list()
print(type(l4))
print(l4)<class 'list'>[]<class 'list'>[100]<class 'list'>[2, 3, 5, 5, 9, 7, 8]<class 'list'>[]# 下标访问列表
l = [3,2,5,1,9,8,7]
print(l[1])2print(l[0])3# 分片操作
# 注意截取的范围,包含左边的下标值,不包含右边的下标值
print(l[1:4])
# 下标值可以为空,如果不写,左边下标值默认为0,右边下标值为最大数加一,即表示截取到最后一个数据
print(l[:])
print(l[:4])
print(l[2:])[2, 5, 1][3, 2, 5, 1, 9, 8, 7][3, 2, 5, 1][5, 1, 9, 8, 7]print(l)
# 分片可以控制增长幅度,默认增长幅度为1
print(l[1:6:1])
# 打印从下标1开始的数字,每次隔一个
print(l[1:6:2])
# 下标可以超出范围,超出后不在考虑多余下标内容
print(l[2:10])
# 下标值,增长幅度可以为负数
# 为负数,表明为从右往左
# 规定: 数组最后一个数字的下标是-1[3, 2, 5, 1, 9, 8, 7][2, 5, 1, 9, 8][2, 1, 8][5, 1, 9, 8, 7]# 分片之负数下标
print(l)
# 下面显示的是为空,因为默认分片总是从左向右截取
print(l[-2:-4])
print(l[-4:-2])
# 如果分片一定左边值比右边大,则步长参数需要使用负数
# 此案例为一个list直接正反截取提供了一个思路
print(l[-2:-4:-1])
print(l[-1:-8:-1])[3, 2, 5, 1, 9, 8, 7][][1, 9][8, 9][7, 8, 9, 1, 5, 2, 3]# id函数举例
a = 100
b = 200
print(id(a))
print(id(b))
# a跟c指向同一份数据
c = a
print(id(c))
a = 101
print(a)
print(c)
print(id(a))
print(id(c))140734817148832140734817152032140734817148832101100140734817148864140734817148832# 通过id可以直接判断出分片是重新生成了一份数据还是使用同一份数据
l = [3,5,6,8,5,43,4,7]
ll = l[:] # 分片操作
lll = ll
# 如果两个id值一样,则表明分片产生的列表是使用的同一地址同一份数据
# 否则,则表明分片是重新产生了一份数据,即一个新的列表,然后把数据拷贝到新列表中
print(id(l))
print(id(ll))
print(id(lll))
# 通过id知道,ll和lll是同一份数据,验证代码如下
l[1] = 100
print(l)
print(ll)
print(lll)
ll[1] = 100
print(ll)
print(lll)185754007380018575400524881857540052488[3, 100, 6, 8, 5, 43, 4, 7][3, 5, 6, 8, 5, 43, 4, 7][3, 5, 6, 8, 5, 43, 4, 7][3, 100, 6, 8, 5, 43, 4, 7][3, 100, 6, 8, 5, 43, 4, 7]原创声明:本文系作者授权腾讯云开发者社区发表,未经许可,不得转载。
如有侵权,请联系 cloudcommunity@tencent.com 删除。
原创声明:本文系作者授权腾讯云开发者社区发表,未经许可,不得转载。
如有侵权,请联系 cloudcommunity@tencent.com 删除。