
我们把符合下列属性的数组 A 称作山脉:
A.length >= 3
存在 0 < i < A.length - 1 使得A[0] < A[1] < ... A[i-1] < A[i] > A[i+1] > ... > A[A.length - 1]给定一个确定为山脉的数组,返回任何满足 A[0] < A[1] < … A[i-1] < A[i] > A[i+1] > … > A[A.length - 1] 的 i 的值。
来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/peak-index-in-a-mountain-array 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。
示例 1:
输入:[0,1,0]
输出:1
示例 2:
输入:[0,2,1,0]
输出:1
class Solution {
public:
int peakIndexInMountainArray(vector<int>& A) {
int left = 1, right = A.size()-2, mid;
while(left <= right)
{
mid = left + ((right-left)>>1);
if(A[mid]>A[mid-1] && A[mid]>A[mid+1])
return mid;
else if(A[mid] < A[mid+1])
left = mid+1;
else
right = mid-1;
}
return -1;
}
};