leetCode175|检查两个字符串数组是否相等

示例 1：

输入：word1 = ["ab", "c"], word2 = ["a", "bc"]
输出：true
解释：
word1 表示的字符串为 "ab" + "c" -> "abc"
word2 表示的字符串为 "a" + "bc" -> "abc"
两个字符串相同，返回 true
示例 2：

输入：word1 = ["a", "cb"], word2 = ["ab", "c"]
输出：false
示例 3：

输入：word1  = ["abc", "d", "defg"], word2 = ["abcddefg"]
输出：true
 

提示：

1 <= word1.length, word2.length <= 103
1 <= word1[i].length, word2[i].length <= 103
1 <= sum(word1[i].length), sum(word2[i].length) <= 103
word1[i] 和 word2[i] 由小写字母组成

import java.util.Arrays;

public  class ArrayStringsAreEqualTest2 {
    public static void main(String[] args) {
        String []word1={"ab","c"};
        String [] word2={"a","bc"};
        boolean arrayStringsAreEqual = arrayStringsAreEqual(word1, word2);
        System.out.println("arrayStringsAreEqual = " + arrayStringsAreEqual);
    }

    public static  boolean arrayStringsAreEqual(String[] word1, String[] word2) {
        if (word1 == null && word2 == null) {
            return true;
        }
        if (word1 == null && word2 != null) {
            return false;
        }
        if (word1 != null && word2 == null) {
            return false;
        }
        String str1=String.join("",Arrays.asList(word1));
        String str2 = String.join("", Arrays.asList(word2));
        return str1.equals(str2);
    }
}