首页
学习
活动
专区
圈层
工具
发布
首页
学习
活动
专区
圈层
工具
MCP广场
社区首页 >专栏 >python 创建类cell数组

python 创建类cell数组

作者头像
py3study
发布2020-01-06 11:23:23
发布2020-01-06 11:23:23
2K00
代码可运行
举报
文章被收录于专栏:python3python3
运行总次数:0
代码可运行

When you do this:

代码语言:javascript
代码运行次数:0
运行
复制
a = np.array([[np.array([[2, 2]]), np.array([[3, 3]])]])

the final call to np.array actually concatenates the inner two, so you get one array at the end:

代码语言:javascript
代码运行次数:0
运行
复制
>>> a
array([[[[2, 2]],

        [[3, 3]]]])

>>> a.shape
(1, 2, 1, 2)

But to mimic a cell array you want to basically have an array of arrays. You can acheive this by setting dtype=object, but you must create the array and set the elements separately to avoid the automatic merging.

代码语言:javascript
代码运行次数:0
运行
复制
three = array([[array([[2, 2, 2]]), array([[3, 3]])]])
two = np.empty(three.shape, dtype=object)
two[0,0,0] = np.array([[2,2]])
two[0,1,0] = np.array([[3,3]])

Then:

代码语言:javascript
代码运行次数:0
运行
复制
sio.savemat('two.mat', {'two': two})

to see what they look like:

代码语言:javascript
代码运行次数:0
运行
复制
>>> two
array([[[array([[2, 2]])],
        [array([[3, 3]])]]], dtype=object)

>>> two.shape
(1, 2, 1)

Note that I may have gotten confused about your desired shape, since you have so many nested brackets, so you might have to reshape some of this, but the idea should hold regardless.

例如:

代码语言:javascript
代码运行次数:0
运行
复制
npose = 5
nsmile = 2

poseSmile_cell = np.empty((npose,nsmile),dtype=object)

for i in range(5):
    for k in range(2):
        poseSmile_cell[i,k] = np.zeros((4,4))


print poseSmile_cell.shape

参考文献:

https://stackoverflow.com/questions/19797822/creating-matlab-cell-arrays-in-python

本文参与 腾讯云自媒体同步曝光计划,分享自作者个人站点/博客。
原始发表:2019/09/21 ,如有侵权请联系 cloudcommunity@tencent.com 删除

本文分享自 作者个人站点/博客 前往查看

如有侵权,请联系 cloudcommunity@tencent.com 删除。

本文参与 腾讯云自媒体同步曝光计划  ,欢迎热爱写作的你一起参与!

评论
登录后参与评论
0 条评论
热度
最新
推荐阅读
领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档