Question :
Given a roman numeral, convert it to an integer.
Input is guaranteed to be within the range from 1 to 3999.
Anwser 1 :
class Solution {
public:
int toNum(char c)
{
switch(c)
{
case 'I':
return 1;
case 'V':
return 5;
case 'X':
return 10;
case 'L':
return 50;
case 'C':
return 100;
case 'D':
return 500;
case 'M':
return 1000;
default:
return 0;
}
}
int romanToInt(string s) {
// Start typing your C/C++ solution below
// DO NOT write int main() function
int ret = 0;
for(int i = 0; i < s.size(); i++)
{
if(i + 1 < s.size())
{
if(toNum(s[i]) < toNum(s[i+1])) // high num < low num, then minus
{
ret -= toNum(s[i]);
}
else
{
ret += toNum(s[i]);
}
}
else
{
ret += toNum(s[i]);
}
}
return ret;
}
};
Anwser 2 :
class Solution {
public:
int toNum(char c)
{
switch(c)
{
case 'I':
return 1;
case 'V':
return 5;
case 'X':
return 10;
case 'L':
return 50;
case 'C':
return 100;
case 'D':
return 500;
case 'M':
return 1000;
default:
return 0;
}
}
int romanToInt(string s) {
// Start typing your C/C++ solution below
// DO NOT write int main() function
int ret = 0;
int len = s.size();
int pre = 1001;
int cur;
for (int i = 0; i < len; ++i)
{
cur = toNum(s[i]);
ret += cur;
if (cur > pre)
{
ret -= 2*pre; // pre already add one time, now minus tow times
}
pre = cur;
}
return ret;
}
};