poj-1503-java大数相加
Description
One of the first users of BIT's new supercomputer was Chip Diller. He extended his exploration of powers of 3 to go from 0 to 333 and he explored taking various sums of those numbers. ``This supercomputer is great,'' remarked Chip. ``I only wish Timothy were here to see these results.'' (Chip moved to a new apartment, once one became available on the third floor of the Lemon Sky apartments on Third Street.)
Input
The input will consist of at most 100 lines of text, each of which contains a single VeryLongInteger. Each VeryLongInteger will be 100 or fewer characters in length, and will only contain digits (no VeryLongInteger will be negative). The final input line will contain a single zero on a line by itself.
Output
Your program should output the sum of the VeryLongIntegers given in the input.
Sample Input
123456789012345678901234567890
123456789012345678901234567890
123456789012345678901234567890
0Sample Output
370370367037037036703703703670第一道java题，好开森；
import java.util.*;
import java.math.*;
import java.io.*;
public class Main{ //外面的Main必须大写！
public static void main(String[] args){ //String S大写
Scanner cin= new Scanner(System.in);
BigDecimal a=BigDecimal.valueOf(0); //组合的函数名一般后个一定得大写： BigInter BigDecimal valueOf（这前不大写） hasNext nextLine；
BigDecimal b=BigDecimal.valueOf(0); //赋初值
String str;
while(cin.hasNext()) //相当于！=EOF
{
str=cin.nextLine(); //下一行输入nextLine
if(str.equals("0")) //equals
{
break;
}
else
{
a=new BigDecimal(str); //强制转化，把str转化成大数
b=b.add(a); //b+a;
}
}
System.out.println(b.toPlainString()); //println，是LN
//toPlainString 以字符形式输出
}
}腾讯云开发者
