You are a product manager and currently leading a team to develop a new product. Unfortunately, the latest version of your product fails the quality check. Since each version is developed based on the previous version, all the versions after a bad version are also bad.
Suppose you have n
versions [1, 2, ..., n]
and you want to find out the first bad one, which causes all the following ones to be bad.
You are given an API bool isBadVersion(version)
which will return whether version
is bad. Implement a function to find the first bad version. You should minimize the number of calls to the API.
1-n个版本,找出第一个出错的版本。
二分,但是一开始总是超时,想破头,最后发现 l + r会溢出int。
// Forward declaration of isBadVersion API.
bool isBadVersion(int version);
class Solution {
public:
int firstBadVersion(int n) {
long long l = 1, r = n;
while(l <= r)
{
int mid = (l + r) >> 1;
if(isBadVersion(mid)) r = mid - 1;
else l = mid + 1;
}
return l;
}
};
扫码关注腾讯云开发者
领取腾讯云代金券
Copyright © 2013 - 2025 Tencent Cloud. All Rights Reserved. 腾讯云 版权所有
深圳市腾讯计算机系统有限公司 ICP备案/许可证号:粤B2-20090059 深公网安备号 44030502008569
腾讯云计算(北京)有限责任公司 京ICP证150476号 | 京ICP备11018762号 | 京公网安备号11010802020287
Copyright © 2013 - 2025 Tencent Cloud.
All Rights Reserved. 腾讯云 版权所有