题意:
The description of the necklace is a string A = a1a2 … am specifying sizes of the particular beads, where the last character am is considered to precede character a1 in circular fashion. The disjoint point i is said to be worse than the disjoint point j if and only if the string aiai+1 … ana1 … ai-1 is lexicografically smaller than the string ajaj+1 … ana1 … aj-1. String a1a2 … an is lexicografically smaller than the string b1b2 … bn if and only if there exists an integer i, i <= n, so that aj=bj, for each j, 1 <= j < i and ai < bi
这么多废话,真正有用的也就是上面两段话,题目求循环字符串中(首尾相接)字典序最小的位置,和《挑战》P381思路一致,在其后构造同样的字符串,输出长度小于n的位置即可。
只不过要注意可能有多个答案,需要选取最小的下标。比如对于aa,答案是1而不是2。此时构造:
a a a a z
1的情况: a a a a z
2的情况: a a a z
输出1而非2
代码如下:
import java.io.BufferedReader;
import java.io.File;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.Arrays;
import java.util.Comparator;
import java.util.Map;
import java.util.StringTokenizer;
public class Main{
String INPUT = "./data/judge/201709/P1509.txt";
public static void main(String[] args) throws IOException {
new Main().run();
}
void read() {
int t = ni();
while (t --> 0) {
String s = ns();
int n = s.length();
StringBuilder sb = new StringBuilder();
sb.append(s);
sb.append(s);
sb.append((char)('z' + 1));
SuffixArray sa = new SuffixArray(sb.toString().toCharArray());
int ans = -1;
for (int i = 0; i <= sb.length(); ++i) {
if (sa.sa[i] < n) {
ans = sa.sa[i] + 1;
break;
}
}
out.println(ans);
}
}
class SuffixArray{
int k = 1;
int n;
Integer[] sa;
int[] rank;
int[] tmp;
SuffixArray(char[] cs){
n = cs.length;
sa = new Integer[n + 1];
rank = new int[n + 1];
tmp = new int[n + 1];
for (int i = 0; i <= n; ++i) {
sa[i] = i;
rank[i] = i < n ? cs[i] : -1;
}
for (k = 1; k <= n; k *= 2) {
Arrays.sort(sa, cmp);
tmp[sa[0]] = 0;
for (int i = 1; i <= n; ++i) {
tmp[sa[i]] = tmp[sa[i - 1]] + (cmp.compare(sa[i - 1], sa[i]) < 0 ? 1 : 0);
}
for (int i = 0; i <= n; ++i) {
rank[i] = tmp[i];
}
}
}
private Comparator<Integer> cmp = new Comparator<Integer>() {
@Override
public int compare(Integer o1, Integer o2) {
int i = o1;
int j = o2;
if (rank[i] != rank[j]) return rank[i] - rank[j];
else {
int ri = i + k <= n ? rank[i + k] : -1;
int rj = j + k <= n ? rank[j + k] : -1;
return ri - rj;
}
}
};
}
FastScanner in;
PrintWriter out;
void run() throws IOException {
boolean oj;
try {
oj = ! System.getProperty("user.dir").equals("F:\\java_workspace\\leetcode");
} catch (Exception e) {
oj = System.getProperty("ONLINE_JUDGE") != null;
}
InputStream is = oj ? System.in : new FileInputStream(new File(INPUT));
in = new FastScanner(is);
out = new PrintWriter(System.out);
long s = System.currentTimeMillis();
read();
out.flush();
if (!oj){
System.out.println("[" + (System.currentTimeMillis() - s) + "ms]");
}
}
public boolean more(){
return in.hasNext();
}
public int ni(){
return in.nextInt();
}
public long nl(){
return in.nextLong();
}
public double nd(){
return in.nextDouble();
}
public String ns(){
return in.nextString();
}
public char nc(){
return in.nextChar();
}
class FastScanner {
BufferedReader br;
StringTokenizer st;
boolean hasNext;
public FastScanner(InputStream is) throws IOException {
br = new BufferedReader(new InputStreamReader(is));
hasNext = true;
}
public String nextToken() {
while (st == null || !st.hasMoreTokens()) {
try {
st = new StringTokenizer(br.readLine());
} catch (Exception e) {
hasNext = false;
return "##";
}
}
return st.nextToken();
}
String next = null;
public boolean hasNext(){
next = nextToken();
return hasNext;
}
public int nextInt() {
if (next == null){
hasNext();
}
String more = next;
next = null;
return Integer.parseInt(more);
}
public long nextLong() {
if (next == null){
hasNext();
}
String more = next;
next = null;
return Long.parseLong(more);
}
public double nextDouble() {
if (next == null){
hasNext();
}
String more = next;
next = null;
return Double.parseDouble(more);
}
public String nextString(){
if (next == null){
hasNext();
}
String more = next;
next = null;
return more;
}
public char nextChar(){
if (next == null){
hasNext();
}
String more = next;
next = null;
return more.charAt(0);
}
}
}